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Andreyy89
3 years ago
10

Help me I don't know nothing about inequality!!!

Mathematics
1 answer:
I am Lyosha [343]3 years ago
3 0
A.x>9

hope this helps

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A student is solving the system of equations below. In which line is a mistake first made?
AlexFokin [52]

Answer:

line 1

Step-by-step explanation:

because

3x + 2y + z = 11 ➡ z = 11 - 3x - 2y

3x and 2y must change sign when transfer to other sid eof equation

5 0
3 years ago
Find the slope of the line through the pair of points a (2,-3) p(2,9)
Katarina [22]
(x₁,y₁) = (2,-3)
(x₂,y₂) = (2,9)

To determine the slope using two points lie on the line, we could use the following formula
m = \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

plug in the numbers
m = \dfrac{9-(-3)}{2-2}
m = \dfrac{9+3}{0}
m = \dfrac{12}{0}
m = undefined

The slope is undefined, the line is vertical
6 0
3 years ago
Solve N=2rt^2-7rx for x​
galben [10]

Answer:

          N - 2 r t²

x =  -   ------------

                7x

Step-by-step explanation:

N = 2 r t² - 7 r x

solve for x

N = 2 r t² - 7 r x

N + (-2 r t²) = (2 r t²  - 7 r x) + (-2 r t²)

N - 2 r t² = 2 r t² - 7 r x - 2 r t²

N - 2 r t²  - 2 r t² +  2 r t² = - 7 r x

N - 2 r t² = 7 r x

therefore,

          N - 2 r t²

x =  -   ------------

                7x

3 0
3 years ago
The Bureau of Labor Statistics reported that the average yearly income of dentists in the year 2005 was $110,000. A sample of 81
Sholpan [36]

Answer:

a) We want to test to determine if there has been a significant increase in the average yearly income of dentists, the system of hypothesis would be:  

Null hypothesis:\mu \leq 110000  

Alternative hypothesis:\mu > 110000  

b) z=\frac{120000-110000}{\frac{36000}{\sqrt{81}}}=2.5    

c) p_v =P(Z>2.5)=0.0062  

We see that the p value is lower than the significance level of 1-0.95=0.05 so then we can conclude that the true mean is significantly higher than 110000 because we reject the null hypothesis.

Step-by-step explanation:

Information given

\bar X=12000 represent the sample mean for the yearly income in 2006 for the dentists

\sigma= 36000 represent the sample population deviation

n=81 sample size  

\mu_o =110000 represent the value that we want to test

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value for the test

a) Hypothesis to verify

We want to test to determine if there has been a significant increase in the average yearly income of dentists, the system of hypothesis would be:  

Null hypothesis:\mu \leq 110000  

Alternative hypothesis:\mu > 110000  

Since we know the population deviation the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

b) Statistic

When we replace the data given we got:

z=\frac{120000-110000}{\frac{36000}{\sqrt{81}}}=2.5    

c) P value

Now we can find the p value using the fact that we are conducting a right tailed test:

p_v =P(Z>2.5)=0.0062  

We see that the p value is lower than the significance level of 1-0.95=0.05 so then we can conclude that the true mean is significantly higher than 110000 because we reject the null hypothesis.

7 0
4 years ago
Does anyone know the Answer to this?
VikaD [51]
... prolly 18 x 34=612 millimeters
6 0
3 years ago
Read 2 more answers
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