What does the line 5x+4y = -6 look like?

Is this correct? the question is asking if the triangle would have a right, acute, or obtuse angle.

IgorLugansk [536]

Answer:

ut ok points from me so I took it from u

6 0

3 years ago

A candy company claims that 25% of the candies in its bags are colored green. Steve buys 32 bags of 32 candies, randomly selects

Luden [163]

Answer:

45.88%

Step-by-step explanation:

We have in this case a binomial distribution when p = 0.25, since the probability is 25%

. The formula that we will use in excel is BINOM.DIST, separated by commas we must put the value of x, n, p and also if it is true or false. We know that n equals 32.

In this case we need to know when x = 7, 8 and 9 and add this, and thus we will obtain the probability:

P (X = 7) + P (X = 8) + P (X = 9)

Excel formulas: = BINOM.DIST (7,32,0.25, FALSE) + BINOM.DIST (8,32,0.25, FALSE) + BINOM.DIST (9,32,0.25, FALSE)

P = 0.1546 + 0.1610 + 0.1431

P = 0.4588

Probability that steve agrees with the company's claim 45.88%

4 0

3 years ago

The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately 63.7 ft.

The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately 708.92 ft.

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ 98.211 ft./s

Learn more here:

brainly.com/question/18591940

8 0

2 years ago

If the diameter of the semicircle is 1.7 centimeters, what is the circumference of the semicircle?

spin [16.1K]

The formula for circumference is $C=2 \pi r$ or $C= \pi d$ . We have a diameter for the semicircle, so let's use the diameter formula. $C= \pi (1.7)$ which is either $C=1.7 \pi$ or C = 5.338 if we multiply pi in as 3.14. BUT this is only half a circle, so we only have half that distance around the outside. Therefore, the circumference of half this circle is 2.669 cm. But we need to add the 24 mm in. 24 mm in centimeters is 2.4 cm. So 2.669 + 2.4 = 5.069

6 0

3 years ago

Pentagon DEFGH is translated 4 units to the right to create pentagon UVXYZ. DE is 5 cm long. What is the length of UV?

Wewaii [24]

Without seeing the picture, we don't know how DE and UV are related.

3 0

3 years ago