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3 years ago

Please help I really need it

Mathematics

2 answers:

mel-nik [20]3 years ago

6 0

Answer:

m = -1/3

Step-by-step explanation:

You have the right idea with the rise and run. We have a run of 15 and a rise (or I guess in this case, a decline) of -5. Slope is rise over run:

-5/15 = -1/3

This means we have a slope of -1/3.

Alternatively, we could just the points and put them into the slope formula.

We have the points (0,25) and (15,20). We can substitute those values into the formula:

m = y₁ - y₂ / x₁ - x₂

m = 25 - 20 / 0 - 15

m = 5/-15

m = -1/3

Works all the same.

NemiM [27]3 years ago

4 0

Answer:

the slope is 3

Step-by-step explanation:

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Solve for x. <br><br> -3x = -15

yuradex [85]

Answer:

x = 5

Step-by-step explanation:

-3x = 15

---- ----

-3 -3

x = 5

7 0

3 years ago

Read 2 more answers

Select all the equations that have {7} as its solution set. 65−2x=6x+9 9−x=14x 3+4x=5x−4 x2+1=8x−5

luda_lava [24]

Answer:

the answer is this hope it helps im not sure if its all right good luck.

Step-by-step explanation:

A. 65-2x=6x+9

B. 9-x=14x

C. 3+4x=5x-4

d is wrong

5 0

3 years ago

Combine the like terms to create an equivalent expression: <br> 2s+(−4s)=?

Sergeeva-Olga [200]

Answer:

$2s+\left(-4s\right)=-2s$ is the equivalent expression as $2s+\left(-4s\right)$ is equal to $-2s$ .

Step-by-step explanation:

Considering the expression

$2s+\left(-4s\right)$

As we know that

Like terms are said to be the terms which hold the same variables raised to the same power.

For example, $3x$ and $2x$ are like terms as they contain the same variable $x$ raised to the same power.

Lets solve the expression

$2s+\left(-4s\right)$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$2s-4s$

$\mathrm{Add\:similar\:terms:}\:2s-4s=-2s$

$-2s$

Therefore,

$2s+\left(-4s\right)=-2s$ is the equivalent expression as $2s+\left(-4s\right)$ is equal to $-2s$ .

Keywords: equivalent expression, like terms

Learn more about equivalent expression from brainly.com/question/8902137

#learnwithBrainly

4 0

3 years ago

A nightclub has approximated the demand for their Thursday night drink special by p^2+200q^2=177, where p is the price (in dol

Irina18 [472]

Answer:

Step-by-step explanation:

Given the approximate demand function of night drink expressed as;

p^2+200q^2=177,

p is the price (in dollars) and;

q is the quantity demanded (in thousands).

Given

p = $7

q = 800

Required

dq/dp

Differentiating the function implicitly with respect to p shown;

2p + 400d dq/dp = 0

400q dq/dp = -2p

200qdq/dp = -p

dq/dp = -p/100q

substitute p and q into the resulting equation;

dq/dp = -7/100(800)

dq/dp = -7/80000

dq/dp = -0.0000875

This means that the rate of change of quantity demanded with respect to the price is -0.0000875

8 0

3 years ago

Please help me with this thankyou

DerKrebs [107]

The answer would be 60

The first think you would need to do would simply 144. Which would be 12.

Then you are going to want to multiply-5 by 12.
Which would be 60.
With 12 as a positive number, being greater or to than 60 then will become a positive.

7 0

2 years ago