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seraphim [82]
3 years ago
6

Please help I really need it

Mathematics
2 answers:
mel-nik [20]3 years ago
6 0

Answer:

m = -1/3

Step-by-step explanation:

You have the right idea with the rise and run. We have a run of 15 and a rise (or I guess in this case, a decline) of -5. Slope is rise over run:

-5/15 = -1/3

This means we have a slope of -1/3.

Alternatively, we could just the points and put them into the slope formula.

We have the points (0,25) and (15,20). We can substitute those values into the formula:

m = y₁ - y₂ / x₁ - x₂

m = 25 - 20 / 0 - 15

m = 5/-15

m = -1/3

Works all the same.

NemiM [27]3 years ago
4 0

Answer:

the slope is 3

Step-by-step explanation:

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= (x-5)(2x+8) = 2(x-5)(x+4)
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If a rectangle has side lengths 5x-y and x+4y what would be the area and perimeter of the rectangle?
Dafna1 [17]

Answer:

<em>Answer is</em><em> </em><em>given</em><em> </em><em>below with explanations</em><em>. </em>

Step-by-step explanation:

given \:  \: l = 5x - y \: and \: \:  b = x + 4y \\ area \: of \: rectangle \:= l \times b \: sq.units \\  = (5x - y)(x + 4y) \\  = 5 {x}^{2}  + 20xy - xy - 4 {y}^{2}  \\  = 5 {x}^{2}  + 19xy - 4 {y}^{2}  \\ perimeter \: of \: rectangle \\  = 2(l + b) \\  = 2(5x - y + x + 4y) \\  = 2(6x + 3y) \\  = 12x + 6y

<em>HAVE A NICE DAY</em><em>!</em>

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A sample of 200 observations from the first population indicated that x1 is 170. A sample of 150 observations from the second po
igor_vitrenko [27]

Answer:

a) For this case the value of the significanceis \alpha=0.05 and \alpha/2 =0.025, we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

z_{\alpha/2} =1.96

If the calculated statistic |z_{calc}| >1.96 we can reject the null hypothesis at 5% of significance

b) Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8  

c)z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708    

d) Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

Step-by-step explanation:

Data given and notation    

X_{1}=170 represent the number of people with the characteristic 1

X_{2}=110 represent the number of people with the characteristic 2  

n_{1}=200 sample 1 selected  

n_{2}=150 sample 2 selected  

p_{1}=\frac{170}{200}=0.85 represent the proportion estimated for the sample 1  

p_{2}=\frac{110}{150}=0.733 represent the proportion estimated for the sample 2  

\hat p represent the pooled estimate of p

z would represent the statistic (variable of interest)    

p_v represent the value for the test (variable of interest)  

\alpha=0.05 significance level given  

Concepts and formulas to use    

We need to conduct a hypothesis in order to check if is there is a difference between the two proportions, the system of hypothesis would be:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

We need to apply a z test to compare proportions, and the statistic is given by:    

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

a.State the decision rule.

For this case the value of the significanceis \alpha=0.05 and \alpha/2 =0.025, we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

z_{\alpha/2} =1.96

If the calculated statistic |z_{calc}| >1.96 we can reject the null hypothesis at 5% of significance

b. Compute the pooled proportion.

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8  

c. Compute the value of the test statistic.                                                                                              

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.    

Replacing in formula (1) the values obtained we got this:    

z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708    

d. What is your decision regarding the null hypothesis?

Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

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defon
The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.

Solve for the hypotenuse of the right triangle formed.
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 cos  θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
tan θ = opposite/adjacent = y/x = -1/1 = -1
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