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lisabon 2012 [21]
3 years ago
12

A truck rental store charges $50 plus 14 each hour use an algebraic expression to find the cost of the truck rental for 5 hours

Mathematics
1 answer:
Liula [17]3 years ago
4 0

f(x)=14x+50

f(5)=14(5)+50

70+50=120

f(5)=120

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ohaa [14]

Answer:

Opposite angles are right angles.

Step-by-step explanation:

There are no right angles in a parallelogram.

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1.name two acute angles in the figure
kirill115 [55]

Answer:

There isn't a figure. But Acute angles are less than 90 degrees(they're small than an L). Remember it by saying "cute" things are small so acute

Step-by-step explanation:

6 0
3 years ago
A garden measuring 10 meters by 7 meters is going to have a walkway constructed all around the perimeter, increasing the total a
SashulF [63]

The width of the pathway is 3m

Step-by-step explanation:

Let the width of the pathway be 'w'

The area will be 130 square meters

The dimensions of the garden is 10 x 7

Area = (10+w) (7+w)

130 = 70 + 17w + w^2

w^2 + 17w - 60 = 0

w^2 +20w - 3w - 60 = 0

w ( w + 20) - 3 ( w + 20) = 0

(w + 20) (w - 3) = 0

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The width of the pathway is 3m

5 0
3 years ago
Can someone explain this to me please will give brainliest
KATRIN_1 [288]
The answer is A. for this, you have to set up a system of equations. the first one will be the area equation. since you know area=length x width, your equation will be LxW=50. the next equation is L=2W, since the length is two times the width. then, plug in 2W for the L in the other equation and you get 2W^2=50. divide by 2 and get W^2=25. square root both sides and you get W=5. plug back into the other equation to find L=10. Then, add the sides of the rectangle for the perimeter. 10+5+10+5=30.
3 0
3 years ago
9/20
Stella [2.4K]

<u>Question:</u>

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

<u>Answer:</u>

The number of real solutions for the equation x^{2}+5 x+7=0 is zero

<u>Solution:</u>

For a Quadratic Equation of form : a x^{2}+b x+c=0  ---- eqn 1

The solution is x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}  

Now , the given Quadratic Equation is x^{2}+5 x+7=0  ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} , b^2 - 4ac is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

4 0
4 years ago
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