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3 years ago

Who can answer the 3x+2y=-6 for the intercepts and to graph it ?? I'm so lost

Mathematics

1 answer:

ELEN [110]3 years ago

7 0

Y-intercept: 3
x-intercept: 2

put (0,3) and (2,0) as points on the graph

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What does the quotiant 35/x represent?

Bumek [7]

When 35 ÷ 7, the quotient would be 5, while 35 would be called the dividend, and 7, the divisor. I hope this helps

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3 years ago

During which month did Mr.Warner spend the most on gas?

Marianna [84]

Mr.Warner spent the most money on gas in August

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3 years ago

Read 2 more answers

Anyone please???????

leva [86]

Answer:

$\boxed{\sf B)\: x=\sqrt{17}}$

Step-by-step explanation:

<u>Use the Pythagorean Theorem</u>

The equation for the Pythagorean Theorem is $\tt a^2+b^2=c^2$

* a and b are the lengths of the legs, and c is the hypotenuse.*

(To know which side is the hypotenuse look at longest side which is across the right angle).

a= x, b=8, c=9

$\sf a^2+b^2=c^2$

Let's Plug in the side lengths:

$\sf x^2+8^2=9^2$

Evaluate 8^2 and 9^2:

$\sf x^2+64=81$

Subtract 64 from both sides:

$\sf x^2+64-64=81-64$

$\sf x^2=17$

Take the square root of both sides:

$\sf x=\sqrt{17}$

___________________________

5 0

2 years ago

Read 2 more answers

A physical education teacher plans to divide the seventh graders at Wilson Middle School into teams of equal size of year-ending

Crank

Step-by-step explanation:

Consider the provided information.

The total number of students are: 24+26+21=71

He wants each team will have the same number of students between 5 and 9.

The number between 5 to 9 are 6, 7 and 8.

The number 71 is a prime number so we need to divide the 71 students in group so that minimum students left without team.

Dividing 6 students in each group.

Number of teams: $\frac{71}{6}$ = 11 teams and 5 students.

Dividing 7 students in each group.

Number of teams: $\frac{71}{7}$ = 10 teams and 1 students.

Dividing 8 students in each group.

Number of teams: $\frac{71}{8}$ = 8 teams and 7 students.

Thus, we can not divide 71 students into equal teams, but 70 divided by 7 gives the least students left out i.e 10 teams each with 7 students and only 1 student will remain at last.

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3 years ago

Find the length of the arc of the circular helix with vector equation r(t) = 2 cos t i + 2 sin t j + tk from the point (2, 0, 0)

USPshnik [31]

$\vec r(t)=2\cos t\,\vec\imath+2\sin t\,\vec\jmath+t\,\vec k$

$\implies\vec r'(t)=-2\sin t\,\vec\imath+2\cos t\,\vec\jmath+\vec k$

$\implies\|\vec r'(t)\|=\sqrt{(-2\sin t)^2+(2\cos t)^2+1^2}=\sqrt5$

Then the length of the arc is

$\displaystyle\int_0^{2\pi}\|\vec r'(t)\|\,\mathrm dt=\sqrt5\int_0^{2\pi}\mathrm dt=2\sqrt5\,\pi$

4 0

3 years ago