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3 years ago

Triangle QRS is a right triangle with the right angle at vertex R. The sum of m∠Q and m∠S must be

Mathematics

2 answers:

Verdich [7]3 years ago

8 0

Answer:

you didn't specify much!

So I am saying they are 45° each and that make the sum of both 90°

Step-by-step explanation:

According to the triangle sum theorem, all the angles in a triangle must add up to 180. If one angle is 90° the other two have to add up to 90°,

sveticcg [70]3 years ago

5 0

Answer:

90 degrees

Step-by-step explanation:

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Will mark Brainliest

olga55 [171]

Answer:

Step-by-step explanation:

This means that 12/(2x+1)=8/(x+4). Cross multiply to get 16x + 8 = 12x + 48. Subtract 12x + 8 from both sides to get 4x = 40, so x = 10.

3 0

3 years ago

How would you simplify <br>(3+i)(4+2i)?

const2013 [10]

Answer:

Step-by-step explanation:

Use FOIL: (a + b)(c + d) = ac + ad + bc + bd

and i² = -1

$(3+i)(4+2i)\\\\=(3)(4)+(3)(2i)+(i)(4)+(i)(2i)\\\\=12+6i+4i+2i^2\qquad\text{combine like terms}\\\\=(12-2)+(6i+4i)\\\\=10+10i$

7 0

3 years ago

Read 2 more answers

Who know how to do this ?

nadya68 [22]

It seems to me this just wants you to add the 3 equations.
2m + 2n +5p

3 0

3 years ago

Please Help me!!!

drek231 [11]

Step-by-step explanation:

The displacement of a particle d (in km) as a function of time t (in hours) is given by :

$d=2t^3+5t^2-3$

Displacement at t = 4 hours,

$d(4)=2(4)^3+5(4)^2-3=205\ km$

Velocity of particle is given by :

$v=\dfrac{dd}{dt}\\\\v=\dfrac{d(2t^3+5t^2-3)}{dt}\\\\v=6t^2+10t$

Velocity at t = 4 hours,

$v=6(4)^2+10(4)=136\ km/h$

Acceleration of the particle is given by :

$a=\dfrac{dv}{dt}\\\\a=\dfrac{d(6t^2+10t)}{dt}\\\\a=12t+10$

At t = 4 hours,

$a=12(4)+10=58\ km/h^2$

Therefore, the displacement, velocity and acceleration at t = 4 hours is 205 km, 136 km/h and 58 km/h² respectively.

7 0

3 years ago

Select all equations for which -3 is a solution.

ad-work [718]

Answer:

look it up

Step-by-step explanation:

7 0

3 years ago