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3 years ago

Triangle QRS is a right triangle with the right angle at vertex R. The sum of m∠Q and m∠S must be

Mathematics

2 answers:

Verdich [7]3 years ago

8 0

Answer:

you didn't specify much!

So I am saying they are 45° each and that make the sum of both 90°

Step-by-step explanation:

According to the triangle sum theorem, all the angles in a triangle must add up to 180. If one angle is 90° the other two have to add up to 90°,

sveticcg [70]3 years ago

5 0

Answer:

90 degrees

Step-by-step explanation:

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lozanna [386]

Answer:

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Step-by-step explanation:

The center is a fixed point in the middle of the circle; usually given the general coordinates (h, k). The fixed distance from the center to any point on the circle is called the radius.

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3 years ago

Plot the point (−12, −52) on the coordinate plane.

irinina [24]

Answer:

Step-by-step explanation:

-12 goes on the x axis (the line that goes ⇄), and because it's negative, it will go to the right.

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3 years ago

How many reflectional symmetries does this figure have?

liubo4ka [24]

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Step-by-step explanation:

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3 years ago

The 400ths power of number is 9^1000 what is the number

chubhunter [2.5K]

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3 years ago

find the value of the trigonometric function sin (t) if sec t = -4/3 and the terminal side of angle t lies in quadrant II

kodGreya [7K]

Answer:

$sin(t) =\frac{\sqrt{7}}{4}$

Step-by-step explanation:

By definition we know that

$sec(t) = \frac{1}{cos(t)}$

and

$cos ^ 2(t) = 1-sin ^ 2(t)$

As $sec(t) = -\frac{4}{3}$

Then

$sec(t) = -\frac{4}{3}\\\\\frac{1}{cos(t)} =-\frac{4}{3}\\\\cos(t) = -\frac{3}{4}$

Now square both sides of the equation:

$cos^2(t) = (-\frac{3}{4})^2$

$cos^2(t) = \frac{9}{16}\\\\$

$1-sin^2(t) =\frac{9}{16}\\\\sin^2(t) =1-\frac{9}{16}\\\\sin^2(t) =\frac{7}{16}\\\\sin(t) =\±\sqrt{\frac{7}{16}}$

In the second quadrant sin (t) is positive. Then we take the positive root

$sin(t) =\sqrt{\frac{7}{16}}$

$sin(t) =\frac{\sqrt{7}}{4}$

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3 years ago