So we can make an equation for this, being 7=1/3x, as that effectively says she can make 3 drawings per page.
Knowing this, we can multiply it by 3 to get x=21 (since if she can draw 3 drawings per page, we can imagine that if each drawing took a page she would need 3 times the pieces of paper), therefore she can make 21 drawings.
20: 1,2,4,5,10,20
28: 1,2,4,7,14,28
6
To solve this problem, you need to divide the total number of students going on the field trips with the number of students in each group.
44/7
= 6 R 2
Since, I assume there can <em>only</em> be groups of 7, the answer is 6.
Answer:
(8)
Step-by-step explanation:
(1+2)=
Answer:
Option A. Only Khaled
Step-by-step explanation:
To know which option is correct, we shall use the formula suggested by both Khaled and Wilma to see which will give the sequence given in the question.
For Khaled:
F(n) = 1 • 3ⁿ¯¹
n = 1
F(n) = 1 • 3ⁿ¯¹
F(1) = 1 • 3¹¯¹
F(1) = 1 • 3⁰
F(1) = 1 × 1
F(1) = 1
n = 2
F(n) = 1 • 3ⁿ¯¹
F(2) = 1 • 3²¯¹
F(2) = 1 • 3¹
F(2) = 1 × 3
F(2) = 3
n = 3
F(n) = 1 • 3ⁿ¯¹
F(3) = 1 • 3³¯¹
F(3) = 1 • 3²
F(3) = 1 × 9
F(3) = 9
For Wilma
F(n) = 1 • 3ⁿ
n = 1
F(n) = 1 • 3ⁿ
F(n) = 1 • 3¹
F(1) = 1 × 3
F(1) = 3
n = 2
F(n) = 1 • 3ⁿ
F(2) = 1 • 3²
F(2) = 1 × 9
F(2) = 9
n = 3
F(n) = 1 • 3ⁿ
F(3) = 1 • 3³
F(3) = 1 × 27
F(3) = 27
SUMMARY
Using Khaled's formula i.e F(n) = 1 • 3ⁿ¯¹ we obtained 1, 3, 9,..
Using Wilma's formula i.e F(n) = 1 • 3ⁿ
We obtained 3, 9, 27,..
Now, comparing the sequence obtained using the formula of both Khaled and Wilma, we can see that only the sequence of Khaled is the same with the one given in the question. Therefore, only Khaled's formula is correct.
