Question

In triangle ABC, mA=35, mB=40, and a=9. Which equation should you solve for b?

Answer 1

Answer:

  B.  sin35/9=sin40/b

Step-by-step explanation:

The law of sines tells you ...

  sin(A)/a = sin(B)/b

Filling in the given values, you get ...

  sin(35°)/9 = sin(40°)/b

Answer 2

Answer:

B.$\frac{sin 35}{9}=\frac{sin 40 }{b}$

Step-by-step explanation:

We are given that in a triangle ABC. $m\angle =35^{\circ}$

$m\angle B=40^{\circ}$

a=9

We have to find an equation  which solve for b

We know that a sine law

$\frac{a}{sine A}=\frac{b}{sinB}=\frac{c}{sinC}$

Using above formula of sine law

Substituting all given values in the above formula of sine law

Then we get

$\frac{9}{sin 35}=\frac{b}{sin 40}$

By cross multiply then we get

$sin 40\times 9=sin35 \times b$

$\frac{sin 40 \times 9}{b}= sin 35$

Using division property of equality

$\frac{ sin 40}{b}=\frac{sin 35}{9}$

Using division property of equality

Hence, option B is true option for solving b.

Answer:B.$\frac{sin 35}{9}=\frac{sin 40 }{b}$