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2 years ago

Solve the following inequality for x. -26+13x+2>2-13x

Mathematics

1 answer:

kolezko [41]2 years ago

4 0

Answer:

x > 1

Step-by-step explanation:

-26 + 13x + 2 > 2 - 13x (Given)

13x - 24 > 2 - 13x (Add like terms)

26x - 24 > 2 (Add 13x on both sides)

26x > 26 (Add 24 on both sides)

x > 1 (Divide 26 on both sides)

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Write a function rule that represents the sentence.

rewona [7]

8 more than half of n is 8 + n/2. That is c.
So,
c = n/2 + 8
or c = 8 + n/2.
The answer is a.

hope this helps!! :)

6 0

3 years ago

Read 2 more answers

For the following amount at the given interest rate compounded continuously, find (a) the future value after 9 years, (b) the

Stella [2.4K]

Answer:

(a) The future value after 9 years is $7142.49.

(b) The effective rate is $r_E=4.759 \:{\%}$ .

(c) The time to reach $13,000 is 21.88 years.

Step-by-step explanation:

The definition of Continuous Compounding is

If a deposit of $P$ dollars is invested at a rate of interest $r$ compounded continuously for $t$ years, the compound amount is

$A=Pe^{rt}$

(a) From the information given

$P=4700$

$r=4.65\%=\frac{4.65}{100} =0.0465$

$t=9 \:years$

Applying the above formula we get that

$A=4700e^{0.0465\cdot 9}\\A=7142.49$

The future value after 9 years is $7142.49.

(b) The effective rate is given by

$r_E=e^r-1$

Therefore,

$r_E=e^{0.0465}-1=0.04759\\r_E=4.759 \:{\%}$

(c) To find the time to reach $13,000, we must solve the equation

$13000=4700e^{0.0465\cdot t}$

$4700e^{0.0465t}=13000\\\\\frac{4700e^{0.0465t}}{4700}=\frac{13000}{4700}\\\\e^{0.0465t}=\frac{130}{47}\\\\\ln \left(e^{0.0465t}\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t\ln \left(e\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t=\ln \left(\frac{130}{47}\right)\\\\t=\frac{\ln \left(\frac{130}{47}\right)}{0.0465}\approx21.88$