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3 years ago

Does anyone know this?

Mathematics

1 answer:

postnew [5]3 years ago

8 0

I believe the second question is Angle-Side-Angle

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(NEED HELP ASAP! PICTURE IS PROVIDED WITH THE QUESTION.)

yuradex [85]

Answer:

i cant see picture

Step-by-step explanation:

7 0

3 years ago

f(x) = (x − 3)(x + 3)[x − (2 − i)][x − (2 + i)] The function has real roots and imaginary roots.

Feliz [49]

The real roots are 3 and -3.
Imaginary roots:-
x - (2 - i) = 0
x = 2 -i is one imaginary root and the other is 2 + i

7 0

3 years ago

Read 2 more answers

Jada says she can find 87-59 by taking away 60 and adding 1 so it is the same as 27+1 or 28. Explain why jadas method to calcula

astraxan [27]

Answer:

The correct answer is 28.

Step-by-step explanation:

Actually Jada makes problem simpler by adding and subtracting 1

that is

87 ₋ 59 ₋1 ₊ 1

so there would be no effect on our final answer because we have added 1 and also subtracted 1

Now,

87 - 59 -1 + 1

87 - 60 +1 ( ∵ -59 - 1 = -60 )

27 + 1 (∵ 87 - 60 = 27 )

so the final answer is 28 .

3 0

3 years ago

What is the product of 306 and 15?

Mars2501 [29]

Product means to multiply.
306 x 15 = 4590.

7 0

3 years ago

Read 2 more answers

. A right cylindrical drum is to hold 7.35 cubic feet of liquid. Find the dimensions (radius of the base and height) of the drum

Drupady [299]

Answer:

$r=1.05\ \text{ft}$

$h=2.12\ \text{ft}$

$20.91\ \text{ft}^3$

Step-by-step explanation:

r = Radius

h = Height

Volume of cylinder = $7.35\ \text{ft}^3$

$V=\pi r^2h\\\Rightarrow h=\dfrac{V}{\pi r^2}\\\Rightarrow h=\dfrac{7.35}{\pi r^2}$

Surface area is given by

$A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi r^2+2\pi r\dfrac{7.35}{\pi r^2}\\\Rightarrow A=2\pi r^2+\dfrac{14.7}{r}$

Differentiating with respect to radius we get

$\dfrac{dA}{dr}=4\pi r-\dfrac{14.7}{r^2}$

Equating with zero we get

$0=4\pi r-\dfrac{14.7}{r^2}\\\Rightarrow 4\pi r=\dfrac{14.7}{r^2}\\\Rightarrow r^3=\dfrac{14.7}{4\pi}\\\Rightarrow r=(\dfrac{14.7}{4\pi})^{\dfrac{1}{3}}\\\Rightarrow r=1.05$

$\dfrac{d^2A}{dr^2}=4\pi-2\times \dfrac{14.7}{r^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=4\pi+2\times \dfrac{14.7}{1.05^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=37.96>0$

So, the value of the function is minimum at $r=1.05$

$h=\dfrac{7.35}{\pi r^2}=\dfrac{7.35}{\pi 1.05^2}\\\Rightarrow h=2.12$

So, the radius and height which would minimize the surface area is 1.05 feet and 2.12 feet respectively.

Surface area

$A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi \times 1.05^2+2\pi 1.05\times 2.12\\\Rightarrow A=20.91\ \text{ft}^3$

The minimum surface area is $20.91\ \text{ft}^3$ .

8 0

3 years ago