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bija089 [108]
3 years ago
13

Does anyone know this?

Mathematics
1 answer:
postnew [5]3 years ago
8 0
I believe the second question is Angle-Side-Angle
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(NEED HELP ASAP! PICTURE IS PROVIDED WITH THE QUESTION.)
yuradex [85]

Answer:

i cant see picture

Step-by-step explanation:

7 0
3 years ago
f(x) = (x − 3)(x + 3)[x − (2 − i)][x − (2 + i)] The function has real roots and imaginary roots.
Feliz [49]
The real roots are 3 and -3.
Imaginary roots:-
x - (2 - i) = 0
x = 2 -i  is one imaginary root and the other is  2 + i
7 0
3 years ago
Read 2 more answers
Jada says she can find 87-59 by taking away 60 and adding 1 so it is the same as 27+1 or 28. Explain why jadas method to calcula
astraxan [27]

Answer:

The correct answer is 28.

Step-by-step explanation:

Actually Jada makes problem simpler by adding and subtracting 1

that is

87 ₋ 59 ₋1 ₊ 1

so there would be no effect on our final answer because we have added 1 and also subtracted 1

Now,

87 - 59 -1 + 1

87 - 60 +1                ( ∵ -59 - 1 = -60 )

27 + 1                       (∵ 87 - 60 = 27 )

28

so the final answer is 28 .

3 0
3 years ago
What is the product of 306 and 15?
Mars2501 [29]
Product means to multiply.
306 x 15 = 4590.
7 0
3 years ago
Read 2 more answers
. A right cylindrical drum is to hold 7.35 cubic feet of liquid. Find the dimensions (radius of the base and height) of the drum
Drupady [299]

Answer:

r=1.05\ \text{ft}

h=2.12\ \text{ft}

20.91\ \text{ft}^3

Step-by-step explanation:

r = Radius

h = Height

Volume of cylinder = 7.35\ \text{ft}^3

V=\pi r^2h\\\Rightarrow h=\dfrac{V}{\pi r^2}\\\Rightarrow h=\dfrac{7.35}{\pi r^2}

Surface area is given by

A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi r^2+2\pi r\dfrac{7.35}{\pi r^2}\\\Rightarrow A=2\pi r^2+\dfrac{14.7}{r}

Differentiating with respect to radius we get

\dfrac{dA}{dr}=4\pi r-\dfrac{14.7}{r^2}

Equating with zero we get

0=4\pi r-\dfrac{14.7}{r^2}\\\Rightarrow 4\pi r=\dfrac{14.7}{r^2}\\\Rightarrow r^3=\dfrac{14.7}{4\pi}\\\Rightarrow r=(\dfrac{14.7}{4\pi})^{\dfrac{1}{3}}\\\Rightarrow r=1.05

\dfrac{d^2A}{dr^2}=4\pi-2\times \dfrac{14.7}{r^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=4\pi+2\times \dfrac{14.7}{1.05^3}\\\Rightarrow \dfrac{d^2A}{dr^2}=37.96>0

So, the value of the function is minimum at r=1.05

h=\dfrac{7.35}{\pi r^2}=\dfrac{7.35}{\pi 1.05^2}\\\Rightarrow h=2.12

So, the radius and height which would minimize the surface area is 1.05 feet and 2.12 feet respectively.

Surface area

A=2\pi r^2+2\pi rh\\\Rightarrow A=2\pi \times 1.05^2+2\pi 1.05\times 2.12\\\Rightarrow A=20.91\ \text{ft}^3

The minimum surface area is 20.91\ \text{ft}^3.

8 0
3 years ago
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