Please help! 25 points! Write the equation of a line with slope 3/2 and Y-Intercept -2.
1 answer:
Hello there!
For this question, we can use slope-intercept form of a line. The following equation is the format for slope-intercept form:
In this equation, m is the slope and b is the y-intercept. The slope and y-intercept is given. Thus, we just "plug in" the given values into the equation to get our answer. Replace "m" with "3/2" and replace "b" with "-2". After doing so, you get the following equation for the line.
That should be your answer. Hope this helps! :)
~AgentCozmo4, Junior Moderator
For this question, we can use slope-intercept form of a line. The following equation is the format for slope-intercept form:
In this equation, m is the slope and b is the y-intercept. The slope and y-intercept is given. Thus, we just "plug in" the given values into the equation to get our answer. Replace "m" with "3/2" and replace "b" with "-2". After doing so, you get the following equation for the line.
That should be your answer. Hope this helps! :)
~AgentCozmo4, Junior Moderator
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Answer:
(3 square root of 2 , 135°), (-3 square root of 2 , 315°)
Step-by-step explanation:
Hello!
We need to determine two pairs of polar coordinates for the point (3, -3) with 0°≤ θ < 360°.
We know that the polar coordinate system is a two-dimensional coordinate. The two dimensions are:
- The radial coordinate which is often denoted by r.
- The angular coordinate by θ.
So we need to find r and θ. So we know that:
(1)
x = rcos(θ) (2)
x = rsin(θ) (3)
From the statement we know that (x, y) = (3, -3).
Using the equation (1) we find that:
Using the equations (2) and (3) we find that:
3 = rcos(θ)
-3 = rsin(θ)
Solving the system of equations:
θ= -45
Then:
r = 3\sqrt{2}[/tex]
θ= -45 or 315
Notice that there are two feasible angles, they both have a tangent of -1. The X will take the positive value, and Y the negative one.
So, the solution is:
(3 square root of 2 , 135°), (-3 square root of 2 , 315°)