Angle 1 and angle 8 are congruent
21.625 is your answer to 865/40
Answer: 5; PO
6; PM
7; MNO
8; QN
9; OQ
10; PQO
Step-by-step explanation:
Answer:
20
Step-by-step explanation:
For the sake of the problem, let's make female workers "x" and male workers "y".
x+y<40 This equation shows that the total number of workers has a max of 40.
30x+20y<1,000 This equation shows that the total cost the manager pays ($30 to each woman, $20 to each man) has a max of $1,000.
Now you can solve for x and y.
X+y<40
-y -y
X<-y+40
Substitute -y+40 in for X in the second equation
30(-y+40)+20y<1,000
-30y+1200+20y<1,000 Distribute
-10y+1,200<1,000 Combine like terms
-10y<-200 Subtract 1,200
y>20 Divide by -10; flip the sign
Since y>20, and y=male workers, you now know that the minimum
number of male workers he should send is 20
Answer:
-4 sqrt(7)/7
Step-by-step explanation:
csc theta = -4/3
csc theta = hypotenuse / opposite side
hypotenuse = 4
opposite = 3
Using the pythagorean theorem
a^2 + b^2 = c^2
3^2 + b^2 = 4^2
9+b^2 = 16
b^2 = 16-9
b^2 = 7
Taking the square root
sqrt(b^2) = sqrt(7)
b = sqrt(7)
We are in the third quadrant so only tan and cot are positive
that means the x and y values are "negative" so a = -3 and b = - sqrt(7)
sec theta = hypotenuse / adjacent
= 4/ - sqrt(7)
rationalizing
-4 sqrt(7)/ sqrt(7)* sqrt(7)
= -4 sqrt(7)/7
