Question

Select the correct answer.

Answer 1

Answer:

Option (B)

Step-by-step explanation:

There are two lines on the graph representing the system of equations.

First line passes through two points (-3, 1) and (-2, 3).

Slope of the line = $\frac{y_2-y_1}{x_2-x_1}$

                           = $\frac{3-1}{-2+3}$

                       m = 2

Equation of the line passing through (x', y') and slope = m is,

y - y' = m(x - x')

Equation of the line passing through (-3, 1) and slope = 2 will be,

y - 1 = 2(x + 3)

y = 2x + 7 ----------(1)

Second line passes through (0, 1) and (-1, 4) and y-intercept 'b' of the line is 1.

Let the equation of this line is,

y = mx + b

Slope 'm' = $\frac{y_2-y_1}{x_2-x_1}$

               = $\frac{4-1}{-1-0}$

               = -3

Here 'b' = 1

Therefore, equation of the line will be,

y = -3x + 1 ---------(2)

From equation (1) and (2),

2x + 7 = -3x + 1

5x = -6

x = $-\frac{6}{5}$

x = $-1\frac{1}{5}$

From equation (1),

y = 2x + 7

y = $-\frac{12}{5}+7$

  = $\frac{-12+35}{5}$

  = $\frac{23}{5}$

  = $4\frac{3}{5}$

Therefore, exact solution of the system of equations is $(-1\frac{1}{5},4\frac{3}{5})$.

Option (B) will be the answer.