Answer:
Option B, Spencer did not factor the polynomial completely; 16x^2−1 can be factored over the integers.
Step-by-step explanation:
<u>Step 1: Factor</u>
256x^4y^2−y^2
y^2(256x^4 - 1)
y^2(16x^2 - 1)(16x^2 + 1)
<em>y^2(</em><em>4x + 1)(4x - 1</em><em>)(16x^2 + 1)</em>
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Answer: Option B, Spencer did not factor the polynomial completely; 16x^2−1 can be factored over the integers.
Answer: 4xy+6x+2x^2
Step-by-step explanation:
4xy-2x+2x^2+8x
we can combine the terms that only have an x (Ax for any number A)
in this case that's -2x and 8x
-2x+8x=6x
the other things can't be combined
thus you end up with
4xy+6x+2x^2
Answer:
B
Step-by-step explanation:
I have to do that exact same paper
