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3 years ago

Find the value of x in a triangle with one side 11 and 1 angle being 28

Mathematics

2 answers:

Kobotan [32]3 years ago

8 0

Answer:

c 12.5

Step-by-step explanation:

cos 28 = adjacent side/ hypotenuse

cos 28 = 11/x

Multiply each side by x

x cos 28 = 11/x *x

x cos 28 = 11

Divide each side by cos 28

x cos 28/ cos 28 =11 /cos 28

x = 11 /cos 28

x =12.45827056

To the nearest tenth

x = 12.5

Andre45 [30]3 years ago

4 0

Answer:

C: 12.5

Step-by-step explanation:

The sides x and 11 could be defined as the Adjacent angle and the Hypotenuse. This means that we will use the cos function to solve this.

First we can set up our equation

$cos28=\frac{11}{x}$

Next we can solve for x by multiplying by x and dividing by $cos 28$

$x=\frac{11}{cos28}\\\\x=12.458\\\\x=12.5$

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Find the value of x in a triangle with one side 11 and 1 angle being 28​

Find the value of x in a triangle with one side 11 and 1 angle being 28