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Brilliant_brown [7]
3 years ago
11

What is the approximate value of y - x

Mathematics
2 answers:
densk [106]3 years ago
8 0

Answer:

D) y -x = Approximate 17.1 degree.

Step-by-step explanation:

Given : Triangle .

To find :  Approximate value of y - x.

Solution : We have given a right angle triangle with

Opposite side = 19.1 in.

Adjacent side = 14 .1 in.

Tan( y ) = \frac{Opposite}{adjacent}.

Plug the values

Tan( y ) = \frac{19.1}{14.1}.

tan(y) = 1.354.

Taking tan inverse both sides.

y = tan^{-1}(1.354).

y = 53.55 degree.

Now, by the sum of angle of triangles is 180 degree.

Angle c + angle y + angle  x = 180.

Plug the variable

90 + 53.55 + x = 180.

83.55 + x = 180

On subtracting both sides by 83.55

x = 36.45 degree

Then ,

y - x = 53 .55 - 36 . 45

y - x = 17.2

Approximate 17.1 degree

Therefore, D) y -x = Approximate 17.1 degree.

grin007 [14]3 years ago
4 0

Answer:

17.2°

Step-by-step explanation:

using the tangent ration in the right triangle

tan y° = \frac{opposite}{adjacent} = \frac{19.1}{14.1}, hence

y = tan^{-1}(\frac{19.1}{14.1}) ≈ 53.6°

tan x° = \frac{14.1}{19.1}, hence

x = tan^{-1}(\frac{14.1}{19.1}) ≈ 36.4°

y - x = 53.6° - 36.4° = 17.2°


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a = 640s
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Suppose that 70% of college women have been on a diet within the past 12 months. A sample survey interviews an SRS of 267 colleg
Fofino [41]

Answer:

The probability that 75% or more of the women in the sample have been on a diet is 0.037.

Step-by-step explanation:

Let <em>X</em> = number of college women on a diet.

The probability of a woman being on diet is, P (X) = <em>p</em> = 0.70.

The sample of women selected is, <em>n</em> = 267.

The random variable thus follows a Binomial distribution with parameters <em>n</em> = 267 and <em>p</em> = 0.70.

As the sample size is large (n > 30), according to the Central limit theorem the sampling distribution of sample proportions (\hat p) follows a Normal distribution.  

The mean of this distribution is:

\mu_{\hat p} = p = 0.70

The standard deviation of this distribution is: \sigma_{\hat p}=\sqrt{\frac{p(1-p}{n}} =\sqrt{\frac{0.70(1-0.70}{267}}=0.028

Compute the probability that 75% or more of the women in the sample have been on a diet as follows:

P(\hat p \geq 0.75)=P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}} \geq \frac{0.75-0.70}{0.028}) =P(Z\geq0.179)=1-P(Z

**Use the <em>z</em>-table for the probability.

P(\hat p \geq 0.75)=1-P(Z

Thus, the probability that 75% or more of the women in the sample have been on a diet is 0.037.

7 0
3 years ago
janice invests a total of 8000 in two different accounts. the first account returns 5%, while the second account returns 8%. if
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Answer:

"She invested $2500 in 5% account and $5500 in 8% account"

Step-by-step explanation:

Let the amount invested in 5% account be "x"

So, the amount invested in 8% account would be "8000 - x"

Interest amount is the percentage multiplied by amount invested. So

Interest of 5% account = 5% of x = 0.05x

Interest of 8% account = 8 % of 8000 - x = 0.08(8000 - x)

Total interest is the sum of these 2 expressions that EQUATES to 565 (given). Let's solve for x:

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and thus,

"8000 - x" = 8000 - 2500 = 5500

Hence,

She invested $2500 in 5% account and $5500 in 8% account

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