Something like this?
h1 = int(input())
m1 = int(input())
s1 = int(input())
h2 = int(input())
m2 = int(input())
s2 = int(input())
s = h2*3600 + m2*60 + s2 - (h1*3600 + m1*60 + s1)
print(s)
Answer:
Growth in the PC platform
Explanation:
Information system technology refers to study, design, implementation, management, support - of computer based information system.
In today's technical growth age : the area has undergone many dynamic changes :
Changes of technical upgradation & application of IT info - Growth in cloud computing, Increased usage of data generated by the Internet of Things, Emerging mobile digital platform, Growing business use of big data
However, Growth of PC platform is not one of the current changes taking place in information systems technology.
Answer:
a) SELECT COUNT(*)
FROM Supplies
WHERE sid=T OR sid=X;
b) SELECT sid
CASE
WHEN sid=IMB AND pid=T
THEN 'YES'
ELSE 'No'
END AS 'check'
FROM Supplies
c) SELECT pid
WHERE partname != computers
FROM Parts
LEFT JOIN Supplies
ON Parts.pid=Supplies.pid;
d) SELECT color
FROM Parts
WHERE pid=T;
Explanation:
a) Here we will use aggregate function along with WHERE and operators to count for specifc part ids
b) This is a CASE query
c) This is again a case query but invloves two separate tables. So, here 1st required values from 1st table are selected and then table is joined with the other table using OUTER JOIN
d) This is again a CASE query. It can be written by calling upon the all the values in one column corresponding to values in another column
