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3 years ago

Please help. Thank you

Mathematics

1 answer:

Luden [163]3 years ago

5 0

what is the approximate speed the ship is traveling in yards per second

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Evaluate the function at the given values:<br><br> f(-1/2)=2x-5

DedPeter [7]

You have the original function as 2x-5
and you are given the value of x to be -1/2

Therefore, all you have to do is substitute the value of x in the function and calculate it as follows:
f(-1/2) = 2(-1/2) - 5 = -1 -5 = -6

7 0

4 years ago

Read 2 more answers

A box is filled with 11 blue cards, 2 green cards, and 7 brown cards. A card is chosen at random from the box. What is the proba

wel

11 blue
2 green
7 brown
total is 20 card
7 out of that 20 are brown
so x out of 100% are brown
7/20=x/100 - cross multiply
700=20x
x=700/20
x=70/2

7 0

3 years ago

What do you do to get this answer and what is the answer

Amanda [17]

Here is your answer

Convert the mixed fraction into into improper fraction.

$7\frac{1}{5} × 2 \frac{1}{6}$

= $\frac{36}{5} × \frac{13}{6}$

= $\frac{6×13}{5}$

= $\frac{78}{5}$

= $15\frac{3}{5}$

HOPE IT IS USEFUL

7 0

3 years ago

Decide if the function is an exponential function. If it is, state the initial value and the base. y = - 1.8 ⋅ 6x

Ipatiy [6.2K]

Answer:

It is an exponential function.

Initial value is - 1.8 and the base is 6.

Step-by-step explanation:

The function is given by $y = - 1.8 (6)^{x}$ and it is an exponential function as the general form of an exponential function is $y = a(b)^{x}$ .

Here, if we put x = 0, the function becomes $y = - 1.8 (6)^{0} = - 1.8$ .

Therefore, the initial value of the function is - 1.8.

In the general equation of exponential function $y = a(b)^{x}$ , b is called the base and x is the exponent.

Therefore, in our case the base of the function $y = - 1.8 (6)^{x}$ is 6. (Answer)

8 0

3 years ago

Ann has her money in a bank account that pays her 2.0% interest each year on the amount of money held in her account. At the end

DIA [1.3K]

$\bf ~~~~~~ \textit{Simple Interest Earned}
\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$1450\\
r=rate\to 2\%\to \frac{2}{100}\to &0.02\\
t=years\to &5
\end{cases}
\\\\\\
I=(1450)(0.02)(5)$

5 0

3 years ago