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Blababa [14]
3 years ago
10

Estion

Mathematics
1 answer:
morpeh [17]3 years ago
6 0

Answer:

79.9 ft

Solution,

Let AB is the Building and MA is Boy's height.

Suppose BC = X feet

In ∆MBC

tan \: 53 =  \frac{ma + ab}{bc}  \\ tan \: 53 =  \frac{106}{x}  \\ tan \: 53 \times x = 106 \\ x =  \frac{106}{tan \: 53}  \\ x = 79.9 \: ft

Hope this helps...

Good luck on your assignment...

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