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3 years ago

Estion

Mathematics

1 answer:

morpeh [17]3 years ago

6 0

Answer:

79.9 ft

Solution,

Let AB is the Building and MA is Boy's height.

Suppose BC = X feet

In ∆MBC

$tan \: 53 = \frac{ma + ab}{bc} \\ tan \: 53 = \frac{106}{x} \\ tan \: 53 \times x = 106 \\ x = \frac{106}{tan \: 53} \\ x = 79.9 \: ft$

Hope this helps...

Good luck on your assignment...

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