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3 years ago

How can this be possible? what should we add to make this true?

Mathematics

2 answers:

FromTheMoon [43]3 years ago

6 0

Answer:

add 2 infront of the zeros

Step-by-step explanation:

20+20+20+20+20=120

or just adda 120 since 0+0+0+0+0+120=120

liberstina [14]3 years ago

3 0

The answer is 120+0+0+0+0

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Please help me!!!!! Its exponents!

Vlad [161]

Answer:

Please check the answer below.

Step-by-step explanation:

Considering the statement

$2^?$

If $?$ is an whole number.

Set of whole number = {0, 1, 2, 3, ....}

Example 1:

When statement is always true:

For x > 0, the statement will be always be true.

Lets put x = 1

$2^1$

2 < 3

So, the statement is true when x = 1

Example 2:

When statement is always true:

For x > 0, the statement will be always be true.

Lets put x = 2

$2^2$

4 < 9

So, the statement is true when x = 2

Example 3:

When statement is Never true:

For x = 0, the statement will never be true.

Lets put x = 0

$2^0$

$\mathrm{Apply\:rule}\:a^0=1,\:a\ne \:0$

$2^0=1, 3^0=1$

So,

$1$

Therefore, the statement is False.

Keywords: exponential number, whole number

Learn more about exponential number from brainly.com/question/3141841

#learnwithBrainly

6 0

3 years ago

Simplify − 2 x × 3 x × − x

Alexus [3.1K]

Answer: 6x^3

Step-by-step explanation:

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3 years ago

An eyewitness observes a hit-and-run accident in New York City, where 95% of the cabs are yellow and 5% are blue. A police exper

Liula [17]

Answer:

0.1739 = 17.39% probability that the cab actually was blue

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Witness asserts the cab is blue.

Event B: The cab is blue.

Probability of a witness assessing that a cab is blue.

20% of 95%(yellow cab, witness assesses it is blue).

80% of 5%(blue cab, witness assesses it is blue). So

$P(A) = 0.2*0.95 + 0.8*0.05 = 0.23$

Probability of being blue and the witness assessing that it is blue.

80% of 5%. So

$P(A \cap B) = 0.8*0.05 = 0.04$

What is the probability that the cab actually was blue?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.04}{0.23} = 0.1739$

0.1739 = 17.39% probability that the cab actually was blue

7 0

3 years ago

If x= 3 and y = 4, then xy -2x=?

pickupchik [31]

Step-by-step explanation:

Given

x = 3 , y = 4

= 3 * 4 - 2 * 3

= 12 - 6

= 6

Hope it will help :)

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3 years ago

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A lawyer charges $100 per month to be put on retainer for a client. The lawyer also charges an hourly rate of $75 for work done.

Marat540 [252]

He would have to work for seven hours

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3 years ago

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