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ryzh [129]
3 years ago
10

A lawyer charges $100 per month to be put on retainer for a client. The lawyer also charges an hourly rate of $75 for work done.

How many hours does the lawyer have to work for a client, in one month, to charge $625?
Mathematics
2 answers:
nekit [7.7K]3 years ago
8 0
Flatrate+changerate=total=625
100+75h=625
minus 100 both sides
75h=525
divide both sides by 75
h=7

answer is 7 hours
Marat540 [252]3 years ago
6 0
He would have to work for seven hours
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I’m pretty sure it’s 370 bc
1 and a half hours is 80+40 (40 is half of 80)
and 2 and a half hours, so 100 for each hour.
100+100+50= 250

250+120=370!!

answer : 370 kilometers per hour
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100.8

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Anton [14]

2 + 4x + 5 = 0

4x + 2 + 5 = 0

4x + 7 = 0

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How? (2x^2 - 3x - 4)(x + 7)<br>​
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Answer:

2 {x}^{3}  +  11{x}^{2}  - 25x - 28

Step-by-step explanation:

Using foil method, Multiply the first term

2 {x}^{2}  \times x = 2 {x}^{3}

Next, Multiply the Outer term in each parenthesis. (2x^2 and 7

2 {x}^{2}  \times 7 = 14 {x}^{2}

2 {x}^{2}  \times 7 = 14 {x}^{2}  \:  \:  \: 3x \times  - x =  - 3x

Then, Multiply the Inner Terms (-3x,-4,7) in each parenthesis

- 3x \times 7 =  - 21x

- 4 \times x =  - 4x

Then multiply the last term (-4 and 7).

- 4 \times 7 =  - 28

Combine it you have

2 {x}^{3}  + 14 {x}^{2}   - 3 {x}^{2}  - 21x - 4x - 28

which simplify to

2 {x}^{3}  + 11 {x}^{2}  - 25x - 28

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