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Zanzabum
4 years ago
5

If the speed of the magnet is doubled, the induced voltage is ________ .

Physics
1 answer:
Marrrta [24]4 years ago
5 0
The answer to your question is TWICE AS GREAT
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When launching a model cannon, students measure the height of the launch point to be 15 m and the horizontal distance the cannon
AVprozaik [17]

Answer:

ummmm

Explanation:

plzzz folllow and anwer my question plzzzz

3 0
4 years ago
4) The components of Vector A are given as follows Ax = -2.4 Ay = + 3.8 What is the magnitude of the A, and what is the angle th
Monica [59]

Answer:

A = 4.49

α = 57.72°

Explanation:

Knowing the magnitude of x & y of a vector we can determine the total magnitude of a vector.

A=\sqrt{A_{x}^{2} +A_{y}^{2} } \\A=\sqrt{(2.4)^{2} +(3.8)^{2} }\\A=4.49

The angle tangent can be used to determine the angle.

tan(\alpha )=\frac{3.8}{2.4}\\tan(\alpha ) =1.5833\\\alpha =tan^{-1}(1.5833) \\\alpha = 57.72 (deg)

5 0
3 years ago
Read through the and calculate the predicted change in kinetic energy of the oblect compared to 50 kg ball traveling at 10 m/s .
Sliva [168]

Answer:

A 50 kg ball traveling at 20 m/s would have 4 times more kinetic energy.

A 50 kg ball traveling at 5 m/s would have 4 times less kinetic energy.

A 50 kg person falling at 10 m/s would have the same kinetic energy.

Explanation:

hope this helps:)

5 0
3 years ago
Given uranium 235 go through an alpha, beta, beta, alpha, gamma, neutron and alpha. What do you have now?
Licemer1 [7]

Answer:

b. 88, 222

Explanation:

235U₉₂ ----→ Alpha --------→  231P₉₀  ----→- beta -----→ 231Q₉₁ ------→-beta -------→231R₉₂--------→-alpha ------→-227S₉₀ ------→ gamma -----→-227S₉₀ ----------→ neutron ------→-226T₉₀-----------→ alpha --------→222 X ₈₈

Atomic No is 88 , atomic weight = 222 .

3 0
3 years ago
How much work is done if you push a box 150 meters with a force of 1.4 N
ss7ja [257]
The work done to push the box is equal to the product between the force and the distance through which the force is applied:
W=Fd
In our problem, the force is F=1.4 N and the distance covered is d=150 m, so the work done by pushing the box is
W=Fd=(1.4 N)(150 m)=210 J
6 0
4 years ago
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