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olya-2409 [2.1K]
3 years ago
13

Given uranium 235 go through an alpha, beta, beta, alpha, gamma, neutron and alpha. What do you have now?

Physics
1 answer:
Licemer1 [7]3 years ago
3 0

Answer:

b. 88, 222

Explanation:

235U₉₂ ----→ Alpha --------→  231P₉₀  ----→- beta -----→ 231Q₉₁ ------→-beta -------→231R₉₂--------→-alpha ------→-227S₉₀ ------→ gamma -----→-227S₉₀ ----------→ neutron ------→-226T₉₀-----------→ alpha --------→222 X ₈₈

Atomic No is 88 , atomic weight = 222 .

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An electric field of 8.20 ✕ 105 V/m is desired between two parallel plates, each of area 25.0 cm2 and separated by 2.45 mm. Ther
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Answer:

q = 1.815 \times 10^{-8} C

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Explanation:

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According to the Gauss's theorem in electrostatics

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3 years ago
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4 0
4 years ago
A 591 μF capacitor is discharged through a resistor, whereby its potential difference decreases from its initial value of 88.5 V
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Answer:

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