Answer:the horizontal displacement is 34.64 meters
The maximum height is 15 meters
Step-by-step explanation:
As the ball moves from the ground at 30 degrees, it travels through a parabolic path. It can therefore be likened to a projectile. The horizontal displacement to where it lands is the range. The formula for determining range,R is
R = U^2Sin2#)/g
Where
U represents the initial velocity of the ball
g is acceleration due to gravity
# represents the angle above the horizontal.
From the information given
# = 30 degrees
U = 20 m/s
g = 10m/s^2
R = 20^2Sin2×30)/10 = (400Sin60)/20 = (400×0.8660)/10
= 34.64 meters
To determine the maximum height of the ball, H,
H = (U^2Sin^2#)/2g
H = (20^2 × Sin^2 30)/2×10
H = (400 × 0.866^2)/20 = 15 meters
There could be one more pentagon
**As far as I know
Answer:
m = 160
p = 90
w = 10
z = 80
y = 10
Step-by-step explanation:
Answer:
XQ = 12
Step-by-step explanation:
In this question it asks for XQ instead of x, but you need to find x first.
1. Find x.
XQ is half of MQ so this statement is true: 3x - 3 = 2(2x - 6)
Solve for x.
3x - 3 = 2(2x - 6)
Distribute 2.
3x - 3 = 4x - 12
Isolate x.
3x = 4x - 9
-x = -9
Divide -1 out.
x = 9
Now solve for XQ, which the equation is given.
XQ = 2(9) - 6
XQ = 18 - 6
XQ = 12
