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3 years ago

9

Can someone help me with this? (20 points if answered) And I will mark the 1st one with brainliest because you have a fat and be

autiful brain :)

2 answers:

Anni [7]3 years ago

8 0

Answer:

If the exponent is positive, move the

Andre45 [30]3 years ago

6 0

If you are dealing with a positive move the little dot to the right and a negative to the left! <3

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Ymorist [56]

Answer:2

Step-by-step explanation: the equation is in linear form y=mx+b, the b represents the y intercept in your equation that would be -5

5 0

3 years ago

Can someone help meee please

hoa [83]

Answer:

Equation → 5y = 3y + 6

Value of ST = 15

Step-by-step explanation:

From the picture attached,

In right triangles ΔVST and ΔVUT,

Acute angles ∠SVT ≅ ∠UVT [Given]

TV ≅ TV [By reflexive property of congruence]

ΔVST ≅ ΔVUT [Hypotenuse angle congruence of right triangles]

Therefore, corresponding parts of the congruent triangles are congruent.

Therefore, ST ≅ TU

5y = 3y + 6

5y - 3y = 6

2y = 6

y = 3

Therefore, ST = 5y

ST = 5(3)

= 15

8 0

2 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):

$y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1 \right)} \, dx$

$y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx$

$y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C$

$C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0$

$C = 0$

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

5 0

3 years ago

25 letters in 4 days

pentagon [3]

In order to write 25 letters in 4 days you would need to write 6.25 a day

5 0

3 years ago

Which set of side lengths forms a right triangle? A) 5 cm, 6 cm,7 cm B) 2 cm, 4 cm, 6 cm C) 8 cm, 9 cm, 11 cm D) 8 cm, 15 cm, 17

Tamiku [17]

A) 5cm,6cm,7cm
you’re welcome

3 0

3 years ago