Answer:
7
Step-by-step explanation:
8 + 12 + 7 + 5 + 2= 34
34/5 =6.8
Rounded =7
The answer is 14 because 14×14=196
15p^2q^2 because you multiply the coefficients and the vaiables. 3x5 is 15, pxp is p^2, and qxq is q^2
Given:
Tangent segment MN = 6
External segment NQ = 4
Secant segment NP =x + 4
To find:
The length of line segment PQ.
Solution:
Property of tangent and secant segment:
If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.



Subtract 16 from both sides.


Divide by 4 on both sides.


The length of line segment PQ is 5 units.