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3 years ago

What is the area of the circle below? Use 3.14 for pi and round to the nearest tenth

Mathematics

2 answers:

IgorC [24]3 years ago

7 0

Answer:

A ) 17.6

Step-by-step explanation:

I'm probably wrong but I did

2.8 x 2 = 5.6

5.6 x 2 = 17.58400

Deffense [45]3 years ago

6 0

The answer is 17.6 i sent you one of my notes about this hope it helps you!

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5. Which is the 8term of the geometric

anygoal [31]

Answer:

Step-by-step explanation:

the numbers are divided by 4 to form a sequence so 64 divided by 4 is 16

4 0

2 years ago

Divide x^3+2 by x+1 long division ppleeease! :)

anzhelika [568]

Long division: (x³ + 2) ÷ (x + 1)

 x² – x + 1 
x³ + 0x² + 0x + 2 | x + 1
– x³ – x² ⋮ ⋮
– x² + 0x ⋮
+ x² + x ⋮
+ x + 2
 – x – 1
+ 1

 Quotient: Q(x) = x² – x – 1;

Remainder: R(x) = + 1.

I hope this helps. =)

3 0

3 years ago

Solve for m: 8(m + 2) = 3(12 - 4m)

Tema [17]

Answer:

m=1

Step-by-step explanation:

step 1: 8(m + 2) = 3(12 - 4m) remove the parentheses

step 2: 8 m + 2 = 3 12 - 4m move the terms

step 3: 8m+ 12m= 36 - 16 collect like terms and calulate

step 4: 20m=20 divide both sides

solution: m=1

3 0

3 years ago

Read 2 more answers

I am sus lol so here is some points

Masja [62]

Hello.

Have a beautiful and joyful day ahead

Thanks for points..

3 0

3 years ago

Given:

diamong [38]

Answer:

10-5 $\sqrt{2}$

Step-by-step explanation:

As per the attached figure, right angled $\triangle MDL$ has an inscribed circle whose center is $I$ .

We have joined the incenter $I$ to the vertices of the $\triangle MDL$ .

Sides MD and DL are equal because we are given that $\angle M = \angle L = 45 ^\circ.$

Formula for area of a $\triangle = \dfrac{1}{2} \times base \times height$

As per the figure attached, we are given that side a = 10.

Using pythagoras theorem, we can easily calculate that side ML = 10 $\sqrt{2}$

Points P,Q and R are at $90 ^\circ$ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of $\triangle$ MIL, $\triangle$ MID and $\triangle$ DIL.

Also,

$\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL$

$\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2$

So, radius of circle = $10-5\sqrt2$

8 0

3 years ago