Let the integers be x, x+1, and x+2
3(x+x+1)=13+4(x+2)
3(2x+1)=13+4x+8
6x+3=4x+21
2x=18
x=9
the integers are 9,10,11
The are of the trapezoid is 125
Answer:
where the triangles are........????
I’m not for sure of the answer but i do know that the two subtractions in the middle would turn into a + and i think you add the -5/8 + 3/10
