The answer is A. The status bar.
Answer:
INPUT "Enter three-digit number" as number
IF number length equals 3 AND is integer:
hundreds = integer of number / 100
tens = inter of (remainder of (number / 100) / 10)
units = remainder of number / 10
PRINT hundreds + " hundreds"
PRINT tens + " tens"
PRINT units + " units"
ELSE:
PRINT "You need to input a three-digit integer"
Explanation:
integer of division is usually obtained by casting to integer with int() (or // in python)
remainder of is usually obtained by using the modulo operator (%)
So, if you know how many number do you expect, you starting diving by 1xx with the same number of digits and go down by always using "remainder" of the last result and integer division of the same amount of digits, until you get to units, that you only use the remainder.
Answer:
True
Explanation:
Some collection of classes or library functions grouped as one name space. A class which belongs to one namespace is different from the class which belongs to another namespace. we can identify a class uniquely with it's namespace .
for ex:
in c#.net
using system;
System.IO;
here System is the namespace which contains class IO
namespace contains any number of classes . In one namespace we can't define two classes with same Name. We can define two classes with same name in different namespaces
Answer:
The statement is as follows:
print("{0:,.1f}".format(number))
Explanation:
Required
Statement to print 1234567.456 as 1,234,567.5
To do this, we make use of the format keyword, and we set the print format in the process.
To round up number to 1 decimal place, we use the following format:
"{0:,.1f}"
To include comma in the thousand place, we simply include a comma sign before the number of decimal place of the output; i.e. before 1
"{0:,.1f}"
So, the print statement is:
print("{0:,.1f}".format(number))