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kirza4 [7]
3 years ago
10

Solve for x. -2(5x+4)-3x+3=-18

Mathematics
1 answer:
Maslowich3 years ago
5 0

Answer:

x=1

Step-by-step explanation:

-2(5x+4)-3x+3=-18

Distribute the -2

-10x -8-3x+3 = -18

Combine like terms

-13x -5 = -18

Add 5 to each side

-13x-5+5 = -18+5

-13x=-13

Divide by -13

-13x/-13 = -13/-13

x =1

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I need help please help me ‼️‼️‼️‼️‼️
motikmotik

Answer:

A, m < $69.43

Step-by-step explanation:

(Could be wrong, I'm just browsing through brainly and thought it looked easy)

I found the percentage of what they've raised by doing 552.5 * .12 (12 percent of 552.5)

This gave me 66.3

We now need to look for how much they need to raise, so you subtract 552.5 by 66.3 to get 486.2.

You need to find out how much each of the 7 members needs to raise to get 486.2, to do this divide 486.2 by 7 to get 69.45.

Ideally, they would raise just this amount and the correct answer would be an equal sign, but since that isn't an option and if they raised less than 69.45 individually they would fail, raising more than 69.45 would pass their goal. So A, more than 69.45 is the answer.

6 0
4 years ago
The table shows the prices for peanut butter sold in jars of different weights. Which size jar is the best buy?
aniked [119]

Answer: 48 oz is the best buy

Step-by-step explanation:

You can get way more for cheaper considering 24oz costs $19.12 and if you do 24x2 you get 48 so if you buy 2 of the 24oz ones you have to pay $18.24

HOPE THIS HELPS ^^

5 0
3 years ago
Kelly's test score is 6 points higher than Mike's
Anna35 [415]

Answer:

Lets mikes point be M

Therefore Kelly's point=M+6

8 0
3 years ago
The mean number of words per minute (WPM) read by sixth graders is 84 with a standard deviation of 15 WPM. If 188 sixth graders
Anna007 [38]

Answer:

0.1836 = 18.36% probability that the sample mean would differ from the population mean by greater than 1.46 WPM

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean number of words per minute (WPM) read by sixth graders is 84 with a standard deviation of 15 WPM.

This means that \mu = 84, \sigma = 15

Sample of 188

This means that n = 188, s = \frac{15}{\sqrt{188}}

What is the probability that the sample mean would differ from the population mean by greater than 1.46 WPM?

Greater than 84 + 1.46 = 85.46 or less than 84 - 1.46 = 82.54. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Probability is is less than 82.54.

P-value of Z when X = 82.54. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{82.54 - 84}{\frac{15}{\sqrt{188}}}

Z = -1.33

Z = -1.33 has a p-value of 0.0918

2*0.0918 = 0.1836

0.1836 = 18.36% probability that the sample mean would differ from the population mean by greater than 1.46 WPM

3 0
3 years ago
How do you show work on 42÷(-6)+23
Darina [25.2K]
42/(-6)+23
-7+23
16 is your answer + work shown

7 0
4 years ago
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