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ZanzabumX [31]
2 years ago
6

If a dice is rolled 240 times how many times do you think it will land on each number?​

Mathematics
1 answer:
4vir4ik [10]2 years ago
4 0

Answer:

being they all have the same amount of chances to be rolled on the same amount  i would say 40

Step-by-step explanation:

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Look at the image below.<br> 7<br> 5<br> 4<br> What is the area of the triangle?
Likurg_2 [28]

Step-by-step explanation:

the area of a triangle is always

baseline × height / 2

where baseline and height are perpendicular (with a 90° angle) to each other.

it does not matter, if the height is inside or outside of the triangle.

so, in our case the area is

4×5/2 = 2×5 = 10 units²

6 0
2 years ago
3.8+(-4.8+(-6.2))=(3.8+(-4.8))+(-6.2)
katrin [286]

-6.2 plus -4.8 is -11. add the 3.8 to get -7.2

-4.8 plus 3.8 is -1

-1 plus -6.2 is -7.2

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4 years ago
Multiply 72.22 and 4.1​
viktelen [127]

Answer: 316.52

Step-by-step explanation:

77.2*4.1 = 316.52

If you have problems with multiplying decimals:

Multiply the numbers just as if they were whole numbers.

1.Line up the numbers on the right - do not align the decimal points.

2.Starting on the right, multiply each digit in the top number by each digit in the bottom number, just as with whole numbers.

3.Add the products.

4 0
3 years ago
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A watering can dispenses water at a rate of 0.40 gallon per minute. The original volume of water in the can was 10 gallons. Whic
andreev551 [17]
The correct answer is B.
3 0
3 years ago
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A transformer increases the input voltage from 12V to 12,000V. What is the ratio of the number of wire turns on the primary coil
erma4kov [3.2K]

Answer:

\frac{n_p}{n_s}=\frac{1}{1000}

Step-by-step explanation:

Given voltage of primary coil is V_p=12V

And voltage of secondary coil is V_s=12,000V

A transformer is a device that contains primary and secondary coil. These coils are mounted on soft iron. The change in voltage depends upon the number of turns of primary coil (n_p) and secondary coil (n_s).

Following equation represents the relation between them.

\frac{V_s}{V_p} =\frac{n_s}{n_p}\\\\\frac{12,000}{12}=\frac{n_s}{n_p}\\\\1000=\frac{n_s}{n_p}

Then, ratio of the number of wire turns on the primary coil to the number of turns on the secondary coil is

\frac{n_p}{n_s}=\frac{1}{1000}

5 0
3 years ago
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