Which solids can have vertical cross sections that are circles? Check all that apply
1 answer:
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Answer:
General Formulas and Concepts:
<u>Pre-Alg</u>
- Order of Operations: BPEMDAS
<u>Alg I</u>
- Slope Formula:
Step-by-step explanation:
<u>Step 1: Define</u>
Point (2, 6)
Point (1, 9)
<u>Step 2: Find slope </u><em><u>m</u></em>
- Substitute:
- Subtract:
- Divide:
To solve for a, you must get a by itself on one side of the equation. Now, a is "joined" to m by multiplication. To "separate" them, use the inverse operation, division.
Divide both sides of the equation by m.
Divide both sides of the equation by m.
<h2>Answer: y = ⁵/₂ x - 13 OR y + 8 = ⁵/₂ x - 5 </h2><h3>Step-by-step explanation:</h3>
<u>Find the slope of the perpendicular line</u>
When two lines are perpendicular, the product of their slopes is -1. This means that the slopes are <em>negative-reciprocal</em>s of each other.
⇒ if the slope of this line = - ²/₅
then the slope of the perpendicular line (m) = ⁵/₂
<u>Determine the equation</u>
We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:
⇒ y - (-8) = ⁵/₂ (x - 2)
∴ y + 8 = ⁵/₂ (x - 2)
We can also write the equation in the slope-intercept form by making y the subject of the equation and expanding the bracket to simplify:
since y + 8 = ⁵/₂ (x - 2)
y = ⁵/₂ x - 13