Answer:
The table that represents the conditional relative frequency is:
A B Total
C 0.25 0.75 1.0
D 0.35 0.65 1.0
Total 0.30 0.70 1.0
Step-by-step explanation:
We know that a conditional relative frequency table is one:
In which the entries in each row is divided by the row total .
OR
In which the entries in each column is divided by the column total.
i.e. the frequency or quantity of an item is being compared either to row or to the column total.
Hence, from the given options, the table that represent the conditional relative frequency is:
A B Total
C 0.25 0.75 1.0
D 0.35 0.65 1.0
Total 0.30 0.70 1.0
The third one because each banner costs $16 and x is the number of banners, $32 is just a one time fee so there is no x.
notice, the circle is missing 1/4, so the area of it is just 3/4 of the whole area of the circle.
![\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=8 \end{cases}\implies A=\pi 8^2\implies A=64\pi \\\\\\ \stackrel{whole}{\cfrac{4}{4}}-\stackrel{one~quarter}{\cfrac{1}{4}}=\cfrac{3}{4}~\hfill \cfrac{3}{4}\cdot 64\pi \implies 48\pi \implies \stackrel{\pi =3.14}{150.72} \\\\\\ ~\hspace{34em}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D8%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%208%5E2%5Cimplies%20A%3D64%5Cpi%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7Bwhole%7D%7B%5Ccfrac%7B4%7D%7B4%7D%7D-%5Cstackrel%7Bone~quarter%7D%7B%5Ccfrac%7B1%7D%7B4%7D%7D%3D%5Ccfrac%7B3%7D%7B4%7D~%5Chfill%20%5Ccfrac%7B3%7D%7B4%7D%5Ccdot%2064%5Cpi%20%5Cimplies%2048%5Cpi%20%5Cimplies%20%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7B150.72%7D%20%5C%5C%5C%5C%5C%5C%20~%5Chspace%7B34em%7D)
Answer:
Olga will use 10 eggs, while Sonja will use 8, thus Olga will use more eggs.
Step-by-step explanation:
Given that Sonja uses 8 of the 12 eggs in her dozen eggs to make a breakfast casserole, while Olga uses 5/6 of a dozen eggs to make scrambled eggs, the following calculations must be performed to determine who uses more eggs:
Sonja = 8/12 = 0.666 x 12 = 8
Olga = 5/6 = 0.83333 x 12 = 10
Therefore, Olga will use 10 eggs, while Sonja will use 8, thus Olga will use more eggs.
Answer:
4y-5x-44=0
Step-by-step explanation:
It passes through one point with the formula being
y-y1=m(x-x1)
y-6=5/4(x-(-4))
y-6=5/4(x+4)
cross multiply
4(y-6)=5(x+4)
4y-24=5x+20
collect like terms
4y-5x=20+24
4y-5x=44
4y-5x-44=0
