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Lemur [1.5K]
3 years ago
9

Marissa is researching information martial art students she found that 7 out of 12martial artist practice every day there are 14

4 martial arts students at a school predict how many students practice every day what is the sample size
Mathematics
2 answers:
svlad2 [7]3 years ago
6 0
<span>So we want to know how many students out of 144 practice martial arts every day if we know that 7/12 practice every day. So lets multiply the numerator and the denumerator with 12. We will get (12*7)/(12*12)=84/144. And we got our answer: 84 out of 144 students practice every day.</span>
aksik [14]3 years ago
6 0

Answer:

84 students out of 144 students practice everyday.

Step-by-step explanation:

Marissa is researching information martial art students, she found that 7 out of 12 martial artist practice everyday.

First we will find the percentage of the sample research.

\frac{7}{12} × 100

= 58.33%

There are 144 martial arts students, so we calculate 58.33% of total students.

\frac{58.33}{100} × 144

= 0.5833 × 144 = 83.995 ≈ 84 students.

84 students out of 144 students practice everyday.

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The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in {52 \choose 7} ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in {7 \choose 2} ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in {45 \choose 7}. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in {7 \choose 2} ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in {38 \choose 7}. And again, we have to choose which ones are the hidden ones, which can be chosen in {7 \choose 2} ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in {31 \choose 7} ways. And choosing which ones are the hidden ones for this player can be done in {7 \choose 2} ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

{52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

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