Answer:
y= 5/11x
Step-by-step explanation:
Step-by-step explanation:
Here with reference angle 45°
Hypotenuse ( h) = y
Perpendicular (p) = x
base (b) = 5√2
We know
tan 45° = p/b
1 = x / 5√2
Therefore x = 5√2
Now
h = √(5√2)^2 + 5√2)^2
= √ 50 +50
= √100
= 10
Hope it helped
Answer:
Option b.
Step-by-step explanation:
Given : 
is right angled triangle . An altitude is drawn from point R to point T on side S Q to form a right angle. The length of S T is 9 and the length of T Q is 16. The length of S R is x.
In the figure, 
and RT is perpendicular to SQ.
We know that in a right angled triangle if a perpendicular is drawn from the vertex of the right angle to the hypotenuse then triangles on both sides of the perpendicular are similar to each other and to the whole triangle .
Therefore , 
Also, we know that if two triangles are similar then their sides are proportional .
So, option b. is correct
Answer: the answer is D.108
Answer:
The price of
1 adult ticket = $15
1 student ticket = $9
Step-by-step explanation:
Let
The price of adult tickets be represented by a
The price of student tickets be represented by s
Therefore:
On the first day of ticket sales the school sold 4 adult tickets and 10 student tickets for a total of $150.
4a + 10s = $150.... Equation 1
The school took in $105 on the second day by selling 1 adult ticket and 10 student tickets.
a + 10s = $105.... Equation 2
a = $105 - 10s
Therefore, we substitute : $105 - 10s = a in Equation 1
4a + 10s = $150.... Equation 1
4($105 - 10s) + 10s = $150
$420 - 40s + 10s = $150
Collect like terms
- 40s + 10s = $150 - $420
-30s = -$270
Divide both sides by -30
-30s/-30 = -$270/-30
s = $9
We find a
a = $105 - 10s
a = $105 - 10($9)
a = $105 - $90
a = $15
Therefore, the price of
1 adult ticket = $15
1 student ticket = $9
