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Radda [10]
3 years ago
8

How to find length of a triangle given one side and angle

Mathematics
1 answer:
mr_godi [17]3 years ago
5 0

Answer:

Use trigonometric ratio

Step-by-step explanation:

Since it is one side and angle of the triangle that is given, it is assumed that the triangle is a right-angled triangle

To solve for one of the two unknown lengths, use trigonometric ratio

There are 3 basic trigonometric ratio namely Sine (sin), Cosine (cos) and Tangent (tan)

Sine of the angle given = opposite side ÷ hypotenuse side

Cosine of the angle given = adjacent side ÷ hypotenuse side

Tangent of the angle given = opposite side ÷ adjacent side

Assuming the length given is the hypotenuse side and the angle is inclined to the horizontal

To find the opposite side of the triangle, multiply the hypotenuse side by the sine of the angle given

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The term "closed" in math means that if you take two items from a set, do some operation, then you'll always get another value in the same set (sometimes you may get the same value as used before). For example, adding two whole numbers leads to another whole number. We therefore say "the set of whole numbers is closed under addition". This applies to integers as well because integers are positive and negative whole numbers. So we can say that integers are closed under addition.

Integers are not closed under division. Take two integers like 2 an 5 and divide: 2/5 = 0.4 which is not an integer. Integers don't have decimal parts.

The set of whole numbers is {0,1,2,3,...} and we can subtract the two values 1 and 2 to get 1-2 = -1. The order matters here. Subtracting a larger value from a smaller leads to a negative. The value -1 is not in the set of whole numbers. So we can say that whole numbers is not closed under subtraction

Finally, the set of irrational numbers is closed under addition. Adding any two irrational numbers leads to another irrational number. For instance, pi+sqrt(2) = 3.142 + 1.414 = 4.556; I'm using rounded decimals as approximate values. An irrational number is one where we cannot write it as a fraction of integers. Contrast that with a rational number in which we can write it as a fraction of integers. Example: 10 = 10/1 is a rational number.

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4 years ago
HELP!! What is the equation of the graphed line?<br> (y=mx+b)
Anettt [7]
So to fine slope you would use the formula down below:

rise/run

So use a graphed point, 0, -5 and you rise or count up quadrants up to a point and then horizontally move to when you find that point.

So from 0,-5 go up 9 vertically, and you would be on the 4

Go horizontal 3 spots and your on a designated point.

So the rise is four and the run is 3

So 4/3 is the slope

In the y= Mx + b equation you would set the equation like this:

y= 4/3 + -5

The m in this formula stands for the slop and the b stands for the y-intercept

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2 years ago
Classify each statement as a definition, postulate,  or theorem. Select the correct answer from the drop-down menu.  through
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postulate,

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3 years ago
A homogeneous rectangular lamina has constant area density ρ. Find the moment of inertia of the lamina about one corner
frozen [14]

Answer:

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Step-by-step explanation:

By applying the concept of calculus;

the moment of inertia of the lamina about one corner I_{corner} is:

I_{corner} = \int\limits \int\limits_R (x^2+y^2)  \rho d A \\ \\ I_{corner} = \int\limits^a_0\int\limits^b_0 \rho(x^2+y^2) dy dx

where :

(a and b are the length and the breath of the rectangle respectively )

I_{corner} =  \rho \int\limits^a_0 {x^2y}+ \frac{y^3}{3} |^ {^ b}_{_0} \, dx

I_{corner} =  \rho \int\limits^a_0 (bx^2 + \frac{b^3}{3})dx

I_{corner} =  \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}

I_{corner} =  \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Thus; the moment of inertia of the lamina about one corner is I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

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