Answer:
Step-by-step explanation:
No, the equation cannot be written with the given information. The distance from the catapult when the watermelon reached the maximum height is needed. Since the watermelon did not start on the ground, it cannot be assumed that the maximum was reached half the distance to the landing point.
Q55.
UTA+ATS=UTS
x+18+120=12x+17
x+138=12x+17
12x-x=138-17
11x=121
x=121/11
x=11
mUTA=x+18
put the value of x
11+18
mUTA=29
Q57.
AQP+RQA=RQP
9x+2+75=1+28x
9x+77=1+28x
28x-9x=77-1
19x=76
x=76/19
x=4
mRQP=1+28x
put the value of x
1+28(4)
1+112
mRQP=113
Find the common denominators. for the miles 5 and 3 go into 15. so 2/5 times 3 is 6/15. and 2/3 times 5 is 10/15. for the hours 5 and 9 go into 45. 1/5 times 9 is 9/45. and 2/9 times 5 is 10/45. so Susan ran 6/15 of a mile in 9/45 of an hour. and Kim ran 10/15 of a mile in 10/45 of an hour.
so Kim ran 3 miles in an hour. Susan ran 2 miles in an hour.
Answer:
The probability is 0.508 = 50.8%.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with a mean weight of 0.8544 g and a standard deviation of 0.0525 g.
This means that 
If 1 candy is randomly selected, find the probability that it weighs more than 0.8535 g.
This is 1 subtracted by the pvalue of Z when X = 0.8535. So



has a pvalue of 0.492
1 - 0.492 = 0.508
The probability is 0.508 = 50.8%.