The answer is 43.5 because you add all of them then divide by 25
Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
Answer: if my calculations are right X= -42x
Step-by-step explanation:
Answer:
3/4
Step-by-step explanation:
2/3 = 4/6 so 5/6 plus 4/6 = 1 3/6 then divide by 2, it will give u 0.75 in decimal form which is simplifyed to 3/4, so 3/4 is the answer.
Answer:
5/8, 3/4, 2/3, 1/2
Step-by-step explanation:
8 is more than 4, 4 is more than 3, 3 is more than 2.
