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MrMuchimi
3 years ago
13

NEED HELP QUICK!! :)

Mathematics
1 answer:
Vlada [557]3 years ago
8 0
Let x and y be your two consecutive whole numbers

x < sqrt(142) < y
x^2 < 142 < y

So, we are looking for x and y such that x^2 < 142 and y^2 > 142.

The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.

11 and 12 are consecutive.

11^2 = 121 < 142 < 144 = 12^2

Thus, 11 and 12 are your numbers

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3 years ago
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Find the equation of the line specified. The line passes through the points ( 5, 2) and ( 6, 4) a. y = 2x - 8 c. y = 2x + 12 b.
o-na [289]
<span>( 5, 2) and ( 6, 4)
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equation
y = 2x - 8

answer
</span><span>a. y = 2x - 8</span>
4 0
3 years ago
Read 2 more answers
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