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3 years ago

13

NEED HELP QUICK!! :)

1 answer:

Vlada [557]3 years ago

8 0

Let x and y be your two consecutive whole numbers

x < sqrt(142) < y
x^2 < 142 < y

So, we are looking for x and y such that x^2 < 142 and y^2 > 142.

The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.

11 and 12 are consecutive.

11^2 = 121 < 142 < 144 = 12^2

Thus, 11 and 12 are your numbers

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