1 - 9
2 -28
3 54
4 -100
5 -60
6 0
7 49
8 -135
9 -96
10 300
11 0
12 192
Answer:
<h3>⇒ A. 2 should be distributed as 2y + 12, y = 6</h3>
Step-by-step explanation:
Here are the steps to solve this equation:
<u>Given:</u>
First step: 2(y+6)-4y
Use the distributive property.
<u>Distributive property:</u>
<h3>
⇒ A(B+C)=AB+AC</h3>
2(y+6)
2*y=2y
2*6=12
2y+12
Isolate the term of y from one side of the equations.
2y+12=4y
Subtract by 12 from both sides.
2y+12-12=4y-12
Solve.
2y=4y-12
Then, you subtract by 4y from both sides.
2y-4y=4y-12-4y
Solve.
2y-4y=-2y
-2y=-12
Divide by -2 from both sides.

Solve.
Divide the numbers from left to right.
<u>Solutions:</u>
-12/-2=6

- <u>Therefore, the correct answer is A. "2 should be distributed as 2y+12, y=6".</u>
I hope this helps. Let me know if you have any questions.
Those are the ranges for one tandard deviation below the mean and one standard deviation above the mean, and we know that 68% of the data falls in that range, so the probability that a randomly chosen worker makes that much is 68%
(-2ab^3)(-3a^2b^5)<span>Simplifying
(-2ab3)(-3a2b5)
Remove parenthesis around (-2ab3)
-2ab3(-3a2b5)
Remove parenthesis around (-3a2b5)
-2ab3 * -3a2b5
Reorder the terms for easier multiplication:
-2 * -3ab3 * a2b5
Multiply -2 * -3
6ab3 * a2b5
Multiply ab3 * a2b5
6a3b<span>8</span></span>
The first one is D and the second is A