If m=5 and n = 2, find the value of 3mn

Two trains leave Cleveland at the same time. One train travels east and the other travels west. The speed of the westbound train

Viefleur [7K]

Answer:

The Eastbound train speed is 76.5 miles per hour and the Westbound train speed is 79.5 miles per hour.

Step-by-step explanation:

1. Let's review all the information provided for solving this question:

Eastbound train speed = x

Westbound train speed = x + 3 miles per hour (The speed of the westbound train is 3mph greater than the speed of the eastbound train)

Duration of trip = 3 hours

Distance between trains after 3 hours = 468 miles

2. Let's find the speed of each train, using the following equation:

3x + 3(x + 3) = 468

3x + 3x + 9 = 468

6x + 9 = 468

6x = 468 - 9 (Subtracting 9 at both sides)

6x = 459

x = 459/6 (Dividing by 6 at both sides)

x = 76.5 miles per hour

The Eastbound train speed is 76.5 miles per hour and the Westbound train speed is 79.5 miles per hour.

3. Proof that x = 76.5 is correct

3x + 3(x + 3) = 468

3 (76.5) + 3 (76.5 + 3) = 468

229.5 + 238.5 = 468

468 = 468

The value of x = 76. 5 is correct. And now we know that the Eastbound train has traveled 229.5 miles since the departure from Cleveland and the Westbound train 238.5 miles.

4 0

3 years ago

Sue ran 7 miles more than Jill last week. Sue ran 11 miles. Which equation will tell you how many miles Jill ran?A) x + 7 = 11B)

strojnjashka [21]

Its A because Sue ran 7 miles more and you’re supposed to add the amount of miles Due ran not subtract them.

3 0

3 years ago

Read 2 more answers

The play director spent 190 190190 hours preparing for a play. That time included attending 35 3535 rehearsals that took varying

sineoko [7]

Answer:

The equation $35x+93\frac{3}{4}=190$ gives average time spent on 35 rehearsals.

Step-by-step explanation:

Please consider the complete question.

The play director spent 190 hours preparing for a play. That time included attending 35 rehearsals that took varying amounts of time and spending $93\frac{3}{4}$ hours on other responsibilities related to the play. What question does the equation $35x+93\frac{3}{4}=190$ help answer?

Since time spent on each rehearsal is 35 hours, so time spent on 35 rehearsals would be $35x$ .

$93\frac{3}{4}$ hours is time spent on other responsibilities related to play. The sum of these times equals to total time spent on preparing the play.

Now let us solve our equation step by step.

$35x+\frac{375}{4}=190$

$35x=190-\frac{375}{4}$

$35x=\frac{760}{4}-\frac{375}{4}$

$35x=\frac{760-375}{4}$

$35x=\frac{385}{4}$

$35x=96.25$

Time spent on 35 rehearsals is 96.25 hours and we are told that each rehearsal took different amount of time. Dividing 96.25 by 35 we will get average time spent on each rehearsal.

Therefore, equation $35x+93\frac{3}{4}=190$ gives average time spent on 35 rehearsals.

8 0

3 years ago

2. Simplify. 10(x + 2)(x – 3) 5(x - 3)(x + 6)

Mariana [72]

Answer:

$10(x + 2)(x - 3) \\ 10x + 20 \times x - 3 \\ 10 {x}^{2} + 17$