Answer:
there are 11 big-bags and 24 small-bags.
Step-by-step explanation:
there are x big-bags and y small-bags.
so now we can know:
(1) x + y = 35
(2) 12x + 7y = 300
in (1),we can do like this:
both left and right x7
then (x + y)x7 = 35 x 7
then 7x + 7y = 35 x 7
then 7x + 7y = 245
now,
(1)7x + 7y =245
(2)12x + 7y = 300
we can both left and right do this: (2) - (1)
then
(12x + 7y) - (7x + 7y) = 300 -245
then
12x + 7y - 7x - 7y = 300 -245
then
12x - 7x +7y - 7y =300 -245
then
5x =55
then
5x ÷ 5 = 55 ÷ 5
then
x = 11
because
x + y =35;x=11
so
11 + y =35
11+ y -11 = 35 -11
then
y = 24
now we know:there are 11 big-bags and 24 small-bags.
Answer: Addition
Step-by-step explanation: You can represent that as 10^5*10^-5
If you add the exponent values, you get 10^0 which is equal to 1. If you multiply them, you get 10^-25 which is wrong.
Answer:
Step-by-step explanation: A GENERAL NOTE: VERTICAL STRETCHES AND COMPRESSIONS
Given a function a new function where is a constant, is a vertical stretch or vertical compression of the function
, then the graph will be stretched., then the graph
, then there will be combination of a vertical stretch or compression with a vertical reflection.HOW TO: GIVEN A FUNCTION, GRAPH ITS VERTICAL STRETCH.Identify the value of Multiply all range values by the graph is stretched by a factor of the graph is compressed by a factor of
, the graph is either stretched or compressed and also reflected about the
EXAMPLE: GRAPHING A VERTICAL STRETCHmodels the number of fruit flies in a population over time, and is graphed below.A scientist is comparing this population to another population, whose growth follows the same pattern, but is twice as large. Sketch a graph of this population.Graph to represent the growth of the population of fruit flies.
Also if you need help here is where i found the info- Lumen learning-
hope this helped :D
Answer:
a) Fx=-5N Fy=-5*sqrt(3) N b) Fx= 5*sqrt(3) N Fy=-5N
c) Fx=-5*sqrt(2) N Fy=-5*sqrt(2) N
Step-by-step explanation:
The arrow's F ( weight) component on axle x is Fx= F*sinA and on axle y is
Fy=F*cosA
a) The x component and y component both are opposite directed to axle x and axle y accordingly. So both components are negative.
So Fx = - 10*sin(30)= -5 N Fy= -10*cos(30)= -10*sqrt(3)/2= -5*sqrt (3) N
b) Now the x component is co directed to axle x , and y component is opposite directed to axle y.
So x component is positive and y components is negative
So Fx = 10*sin(60)= 5*sqrt(3) N Fy= -10*cos(60)= -10*1/2= -5 N
c)The x component and y component both are opposite directed to axle x and axle y accordingly. So both components are negative.
So Fx = - 10*sin(45)= -5*sqrt(2) N
Fy= -10*cos(45)= -10*sqrt(2)/2= -5*sqrt (2) N
