What is the equation of the circle described below. Center (-1, 4), radius = √3

Evgesh-ka [11]

Answer: 10

Step-by-step explanation: The diameter is twice the radius

3 0

2 years ago

According to the National Postsecondary Student Aid Study conducted by the U.S. Department of Education in 2008, 62% of graduate

Ronch [10]

The standard error for the distribution of sampling proportions will be 0.0686.

<h3>What is standard error for the distribution of sampling proportions?</h3>

In mathematics, the difference between a data set and the populace's true average is known as primary data deviation from the mean.

According to the National Postsecondary Student Aid Study conducted by the U.S.

Department of Education in 2008, 62% of graduates from public universities had student loans.

We randomly select 50 students at a time.

Then the standard error for the distribution of sampling proportions will be

$\rm Standard\ error = \sqrt{\dfrac{p(1-p)}{n}}\\\\Standard\ error = \sqrt{\dfrac{0.62(1-0.62)}{50}}\\\\Standard\ error = 0.0686$

More about the standard error for the distribution link is given below.

brainly.com/question/14524236

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6 0

2 years ago

Hello, I need help with this question.

ella [17]

Answer:

The answer would be 22/12 or 1 and 11/12

Step-by-step explanation:

1/2+2/3+3/4

First get common denominators so you have a denominator of 12 so 6/12+8/12+9/12

Add those together and you get 23/12 but you have to subtract one because that's what the problem says so you get 22/12

4 0

3 years ago

Read 2 more answers

Mario’s speed while riding his bike is shown in the graph.

e-lub [12.9K]

Answer:

99fht

Step-by-step explanation:

3 0

3 years ago

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is: