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3 years ago

What is the equation of the circle described below. Center (-1, 4), radius = √3

Mathematics

1 answer:

Brums [2.3K]3 years ago

7 0

same problem asked and answered here:

brainly.com/question/3583159

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Prove the following identity true. Show work.

yulyashka [42]

Answer:

The Pythagorean identity states that

$\sin^2 t + \cos^2 t = 1$

Using that we can rewrite the left denominator as:

$1 - \sin^2 t$

Which can be factored as

$(1 - \sin t)(1+ \sin t)$

The numerator we can expand as:

$(1 - \sin t)(1 - \sin t)$

On the right hand side, let's multply numerator and denominator with (1 - sin t):

The total formula then becomes:

$\dfrac{(1-\sin t)(1-\sin t)}{(1 - \sin t)(1 + \sin t)} = \dfrac{(1-\sin t)(1 - \sin t)}{(1+\sin t)(1 - \sin t)}$

There you go... left and right are equal.

3 0

3 years ago

Read 2 more answers

Who can help and explain these 2 questions

Dominik [7]

Coefficients are added together because they are like terms, this can be proven with the distributive property. For example, x(2x+x)=2x^2+x^2=3x^2.

The commutative property of addition and the associative property demonstrate this.

The word "commutative" comes from "commute" or "move around", so the Commutative Property<span> is the one that refers to moving values around.
</span>
The associative property<span> states that you can add or multiply regardless of how the numbers are grouped. </span>

6 0

4 years ago

An office supply company produces yellow document envelopes. The envelopes come with a variety of sizes, but the length is alway

IceJOKER [234]

P= 2(2w+4)+2w
P=4w+8+2w
P= 6w+8 is the answer

6 0

3 years ago

A particular isotope has a half-life of 74 days. If you start with 1 kilogram of this isotope, how much will remain after 150

shtirl [24]

$\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}$

$\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}$

6 0

3 years ago

Pls HELP, WILL GAVE A 5 STAR RATING AND BRAINLIEST

bonufazy [111]

Answer:

Step-by-step explanation:

-7x-3=2-7x-5

cancel equal terms

-3=2-5

calculate the difference

-3= -3

This statement is true.

6 0

3 years ago