The approximate area of the unshaded region under the standard normal curve is 0.86 the option third is correct.
It is given that the standard normal curve shows the shaded area in the curve.
It is required to find the approximate area of the unshaded region under the standard normal curve.
<h3>What is a normal distribution?</h3>
It is defined as the continuous distribution probability curve which is most likely symmetric around the mean. At Z=0, the probability is 50-50% on the Z curve. It is also called a bell-shaped curve.
In the curve showing the shaded region area between:

First, we calculate the shaded region area:
From the data given the value of Ф(1) = 0.8413.
P(Z<1) = 0.8413 and
P(Z<2) = 0.9772
The area of the shaded region:
= P(Z<2) - P(Z<1)
= 0.9772 - 0.8413
= 0.1359
The area of the unshaded region:
= 1 - The area of the shaded region ( because the curve is symmetric)
= 1 - 0.1359
= 0.8641 ≈ 0.86
Thus, the approximate area of the unshaded region under the standard normal curve is 0.86 the option third is correct.
Know more about the normal distribution here:
brainly.com/question/12421652
The answer should be 0.0004702
The answer is: " x = 11 ¼ " ; or write as: " x = 11.25 " .
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Explanation:
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(40*9) ÷ (4*8) = x ; Solve for "x" ;
(40 * 9 = 360) .
(4 * 8 = 32) .
(360) ÷ (32) = 45/4 = 11 ¼ ; or write as: 11.25 .
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Answer:
The rule that represents the function is
therefore the function is 
Step-by-step explanation:
We have 5 ordered pairs in the plane xy. This means that <em>every pair has the form (x, y).</em>
Then, we have 5 values of x, which will give us 5 values of y, using the rule that represents the function.
<u>The easy evaluation is that when x=0, the value of y is y=1,</u> and then we can evaluate the rule for x=-1, and x=1, <em>the value of y is the same, y=2</em>. We can see here that we have a parabolic function, that is not centered in the origin of coordinates because when x=0, y=1.
So <u>we propose the rule </u>
<u> which is correct for the first 3 values of x.</u>
Now, <em>we evaluate the proposed rule when x=2, and when x=3</em>. This evaluations can be written as


Therefore, the rule is correct, and the function is
