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3 years ago

3x + 5 - x = 9x - 7 + 12

Mathematics

1 answer:

Iteru [2.4K]3 years ago

4 0

Answer:Combine like terms

−

{\color{#c92786}{3x}}+5{\color{#c92786}{-x}}=9x-7+12

3x+5−x=9x−7+12

−

{\color{#c92786}{2x}}+5=9x-7+12

2x+5=9x−7+12

Add the numbers

Subtract the same term from both sides of the equation

Simplify

Subtract the same term from both sides of the equation

Simplify

Divide both sides of the equation by the same term

Simplify

HOPE THIS HELPS :)

Step-by-step explanation:

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The area of a triangle whose height is 1 more than 6 times its base is 13 square feet. If the base of the triangle is x feet, wh

pogonyaev

We must know that the are of the triangle is given by definition by
A = (1/2) * (b) * (h)
where
b = base
h = height
Substituting the values
A = (1/2) * (x) * (1 + 6x)
A = (1/2) * (x + 6x ^ 2)
Since the area is 13 then
(1/2) * (x + 6x ^ 2) = 13
Clearing x we have
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answer
the base is x = 2
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Given g(x) = -2x + 3, solve for x when g(x) = -3.

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How to find y-intercept of 2x - 5y + 15

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4 years ago

PLEASE HELP ASAP

rusak2 [61]

There's a lot of different approaches to this question, but the easiest one I see is this:

If a chord goes through the center of the circle, it is a diameter. That's 180 degrees we don't have to worry about. 47 is an inscribed angle, so we can multiply it by two to get 94 degrees. Subtract 94 from 180 to get 86.

See y? It's also an inscribed angle. To get it, we just take the 86 we just found for the remaining arc and divide by two.

The measure of y is 43.

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A very large batch of parts (assume a normal distrbution0 from a manufacturer has a mean weight = 43g and a standard deviation =

AVprozaik [17]

Answer:

5.44% probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Percentage of parts with weights exceeding 45g?

1 subtracted by the pvalue of Z when X = 45. So

We have $\mu = 43, \sigma = 4$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{45 - 43}{4}$

$Z = 0.5$

$Z = 0.5$ has a pvalue of 0.6915

1 - 0.6915 = 0.3075

If you slect 16 parts at random form that batch, what is the probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g?

This is P(X = 8) when n = 16, p = 0.3075. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{16,8}.(0.3075)^{8}.(0.6915)^{8} = 0.0544$

5.44% probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g

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3 years ago