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BaLLatris [955]
4 years ago
15

How can x+8=-x+7 be set up as a system of equations A. Y=x+8 Y=-x+7 B. y=x+8 Y=-3x+7 C. Y=x+5 Y=-2x+11 D. Y=8 Y=-3x+7

Mathematics
2 answers:
ch4aika [34]4 years ago
8 0
X + 8 = -x + 7

it can be set up like this :
y = x + 8
y = -x + 7
Alla [95]4 years ago
7 0
it is the first choice
y=x+8
y= -x+7

x+8=-x+7
x+x=7 - 8

2x= -1
x= -1/2
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5.00 minus2.40minus1.33= plz show me how you got that answer step by step
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Answer:

5.00 -2.40= 2.60

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The answer is 1.27

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

5 0
3 years ago
The graph below shows the solution to which system of inequalities?
nlexa [21]

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Option D.

Step-by-step explanation:

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Take point (0,0)

On putting this point in inequation y\leq \frac{3x}{4}+10 , we get

0\leq 10 which is true . So, solution is region towards the origin i,e region below the line y= \frac{3x}{4}+10 including the line itself .

On putting (0,0) in inequation y\leq \frac{-x}{2}-3 , we get 0\leq -3 which is false , so solution is region away from the origin i.e region below line y= \frac{-x}{2}-3 including the line itself .

So, common solution to both the inequations is the shaded part in the given figure .

In other words, we can say that the graph shown in the given figure represents system of equations: y\leq \frac{3x}{4}+10\,,\,y\leq \frac{-x}{2}-3

5 0
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