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2 years ago

Divide. −4 2/5÷(−5) −22/25 −8/25 8/25 22/25

Mathematics

2 answers:

postnew [5]2 years ago

8 0

Answer:

The correct answer is 22/25

Step-by-step explanation:

So how I got 22/25 is I Subtract: 2/25 Subtract: 7-8- 4-5= 7 · 5-8 · 5- 4 · 8-5 · 8 = 35-40- 32-40= 35 - 32-40= 3-40 The common denominator you can calculate as the least common multiple of the both denominators - LCM(8, 5) = 40 Power: 3-40^ 2 = 32-402= 22/25

Hope this helped!! :)

^-^

Alika [10]2 years ago

5 0

−4 2/5÷(−5)

−22/25

The answer is 8/25

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Solve this equation<br> 16(1/4x-1/2)>24-2x

jekas [21]

Answer:

x>14

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

−4>−2x+24

Step 2: Flip the equation.

−2x+24<−4

Step 3: Subtract 24 from both sides.

−2x+24−24<−4−24

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Step 4: Divide both sides by -2.

−2x−2<−28−2

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If ƒ={(5, 1),(6, 2),(7, 3),(8, 1),(9, 7)}, then the range of ƒ is {(1, 5),(2, 6),(3, 7),(1, 8),(7, 9)} {1, 2, 3, 7} {5, 6, 7, 8,

navik [9.2K]

Answer:

{1,2,3,7}

Step-by-step explanation:

The range of a relation is the set of y-values of the ordered pairs.

The given relation is:

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The gravitational force exerted by the planet Earth on a unit mass at a distance r from the center of the planet is:

jolli1 [7]

Answer:

Yes, F is a continuous function of r

Step-by-step explanation:

We are given that

When r<R

$F(r)=\frac{GMr}{R^3}$

$r\geq R$

$F(r)=\frac{GM}{r^2}$

Where M=Mass of the earth

R=Radius of earth

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We have to find the function is continuous of r or not.

LHL

$\lim_{r\rightarrow R-}\frac{GMr}{R^3}=\frac{GMR}{R^3}=\frac{GM}{R^2}$

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$\lim_{r\rightarrow R+}\frac{GM}{R^2}=\frac{GM}{R^2}$

$F(R)=\frac{GM}{R^2}$

When a function is continuous at x=a

Then, LHL=RHL=f(a)

RHL==LHL=F(R)

Hence, the function is continuous of r.

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