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shtirl [24]
3 years ago
14

What is the function, domain, and range?? {(1,-2), (-2,0), (-1,2), (1,3)}

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
8 0
If u try graphing them on Desmos then u can see what the domain and range is from that.
scoundrel [369]3 years ago
3 0

Answer:

the relation is NOT a function

domain: { 1,-2,1}

range:  { -2, 0, 2, 3}

Step-by-step explanation:

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Step-by-step explanation:

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In the last six months, Sonia's family used 529, 499, 651, 652, 1,163, and 310 minutes on their cell phone plan. To save money,
Tresset [83]

Answer:

They went over their goal for the last six months by 34 minutes per month.

Step-by-step explanation:

Mean of a data-set:

The mean of a data-set is the sum of all values in the data-set divided by the size of the data-set.

529, 499, 651, 652, 1,163, and 310 minutes on their cell phone plan.

The mean is:

M = \frac{529+499+651+652+1163+310}{6} = 634

By how many minutes did they go over their goal in the last six months?

The mean was of 634 minutes, and they wanted to keep it below 600. So

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4 0
3 years ago
(a) Find parametric equations for the line through (1, 4, 4) that is perpendicular to the plane x − y + 2z = 7. (Use the paramet
Alex777 [14]

Answer:

x=1+t\\y=4-t\\z=4+2t

Step-by-step explanation:

A vector perpendicular to the plane ax+by+cz+d=0 is of the form (a,b,c).

So, a vector perpendicular to the plane x − y + 2z = 7 is (1,-1,2).

The parametric equations of a line through the point (x_0,y_0,z_0) and parallel to the vector (a,b,c) are as follows:

x=x_0+at\\y=y_0+bt\\z=z_0+ct

Put (x_0,y_0,z_0)=(1,4,4) and (a,b,c)=(1,-1,2)

Therefore,

x=1+t\\y=4-t\\z=4+2t

xy-plane:

Put z = 0 ⇒ t = -2 ⇒x = - 1 , y = 6

So, at point (-1,6,0)

yz-plane:

Put x = 0 ⇒ t = -1 ⇒ y = 5, z =2

So, at point (0,5,2)

xz-plane:

Put y = 0 ⇒ t = 4 ⇒ x = 5, z = 12

So, at point (5,0,12)

5 0
3 years ago
254,817- 13?,125=118,692
Alexeev081 [22]

Answer:

118,692

Step-by-step explanation:

7 0
3 years ago
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