Answer:
E. 27/64
Explanation:
Knowing that the couple is heterozygous (Aa) for Niemann-Pick disease, they can have children with the following pairs of alleles:
A x A = AA (Dominant homozygous - Unaffected)
A x a = Aa (Heterozygous - Unaffected)
a x A = Aa (Heterozygous - Unaffected)
a x a = aa (Recessive homozygous - Affected)
So each allele pair has a probability of:
AA = 1/4
Aa = 1/4
Aa = 1/4
aa = 1/4
As the disease only affects recessive homozygous individuals (aa), the probability of an unaffected child being born is 3/4.
Since the couple expects to have three children, the probability of neither being born with the disease is obtained by multiplying the probability of each, as follows:

Thus, it is concluded that the probability of none of the children having Niemann-Pick syndrome is 27/64.
Answer and Explanation:
Ah, sorry for the wait, Kami. <3
You can complete the Lab Report by asking yourself the questions given on the LR Guide. Scroll down to Page 5 of 6 to see the questions. I emailed them to you, so be sure to check them out!
<em>Love you, Kami! </em>
Human dna was completely mapped