Answer:
Option A, They have enzymatic properties that can covalently modify DNA.
Explanation:
Histones have very basic nature and possess no enzymatic properties. However, any modification of DNA is carried out after the end of translation process with the help of enzymes on the N –terminal tails through processes such methylation, acetylation, citrullination, phosphorylation.
There are several Histone-modifying enzymes in the human genome that interact with the non-histone proteins to form functional complexes
Hence, option A is correct
Answer:
The correct answer is -
Parental - BB and bb
F1
Genotypes: 100% Bb
F2
Genotypes: ¼ BB, ½ Bb, ¼ bb
Explanation:
It is given that a cross between a brown and a silver-blue mink produces all brown offspring and it is only possible if brown is dominant over silver blue in true breed cross, assume brown trait is represented by B and silver-blue is b then parents will be
BB and bb
B B
b Bb Bb
b Bb Bb
Cross between F1 individuals: Bb cross Bb
gametes : B, b and B, b
B b
B BB Bb
b Bb bb
the genotype of F2 : 1:2:1 = ¼ BB, ½ Bb, ¼ bb
The skin on the palmar surface of the hands and feet forms ridges, so-called papillary ridges, in patterns that are unique to each individual and which do not change over time. Even identical twins (who share their DNA) do not have identical fingerprints.
